what the reasoning of arguments in return statement of bind function

Question

I took this code from Leaflet api.

no idea what args and arguments is doing in return fn.apply(obj, args || arguments);

bind: function (fn, obj) { // (Function, Object) -> Function
        var args = arguments.length > 2 ? Array.prototype.slice.call(arguments, 2) : null;
        return function () {
            return fn.apply(obj, args || arguments);
        };
    },

See developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — haim770
– haim770, Commented Jan 6, 2015 at 15:15
This looks wrong to me 'cos it doesn't let the user bind persistant args and enter their own args at the same time — Paul S.
– Paul S., Commented Jan 6, 2015 at 15:15

Quentin · Accepted Answer · 2015-01-06 15:18:24Z

2

If you call bind with more than 2 arguments, then it will store those arguments. When you call the function returned by bind, then it will call it using those arguments.

If you call bind with 2 or fewer arguments, then when you call the function returned by bind, it will call it with the arguments you pass at the time.

This does not appear to be a correct implementation of bind. If you want a bind polyfill, then use the one from MDN

answered Jan 6, 2015 at 15:18

Quentin

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