I have a string like this:
data='WebSpherePMI_jvmRuntimeModule_ProcessCpuUsage'
I need to get rid of everything until the first instance of the underline (inclusive) in regex.
I've tried this:
re.sub("(^.*\_),"", data)
but this get rids of everything before all underlines
ProcessCpuUsage
I need it to be:
jvmRuntimeModule_ProcessCpuUsag
Use this instead:
from string import find
data='WebSpherePMI_jvmRuntimeModule_ProcessCpuUsage'
result = data[find(data, "_")+1:]
print result
re.sub("(^.*\_),"", data)
This makes . match every character in the line. Once it gets to the end, and can't match any more ".", it goes to the next token. Oops, that's a underscore! So, it backtracks back before the _ProcessCpuUsage, where it can match a underscore at the start, and then complete the match.
You should ask the . multiplier to be less greedy. You also do not need to capture the contents. Drop the parens. The backslash does nothing. Drop it. The leading line-start anchor also does nothing. Drop it.
re.sub(".*?_,", data)
You have become a victim of greedy matching. The expression matches the longest sequence that it possibly can.
I know there's a way to turn off greedy matching, but I never remember it. Instead there's a trick I use when there's a character I want to stop at. Instead of matching on every character with . I match on every character except the one I want to stop at.
re.sub("(^[^_]*\_", "", data)
This should do:
import re
def get_last_part(d):
m = re.match('[^_]*_(.*)', d)
if m:
return m.group(1)
else:
return None
print get_last_part('WebSpherePMI_jvmRuntimeModule_ProcessCpuUsage')
you can use str.index:
>>> data = 'WebSpherePMI_jvmRuntimeModule_ProcessCpuUsage'
>>> data[data.index('_')+1:]
'jvmRuntimeModule_ProcessCpuUsage'
Using str.split
>>> data.split('_',1)[1]
'jvmRuntimeModule_ProcessCpuUsage'
Using str.find:
>>> data[data.find('_')+1:]
'jvmRuntimeModule_ProcessCpuUsage'
Take a look at string methods Here
Try this regex:
result = re.sub("^.*?_", "", text)
What the regex ^.*?_ does:
^ .. Assert that the position is at the beginning of the string..*? .. Match every character that is not a linebreak character
between zero and unlimitted times as few times as possible.- .. Match the character _Try using split():
s = 'WebSpherePMI_jvmRuntimeModule_ProcessCpuUsage'
print(s.split('_',1)[1])
Result:
jvmRuntimeModule_ProcessCpuUsage
