Regular Expression doesn't Match with string

Question

I am trying to use Regular Expressions to find a string sequence inside a string.

The pattern i am looking for is:

dd.dd.dddd dd:dd:dd //d is a digit from 0-9

my regex is:

Regex r = new Regex(@"(\d[0-9]{2}.\d[0-9]{2}.\d[0-9]{4}\s\d[0-9]{2}:\d[0-9]{2}:\d[0-9]{2})$");

I am now trying to check, if the string "27.11.2014 09:14:59" is Matching to the regex, but sadly it isn't matching.

string str= "27.11.2014 09:14:59";
Regex r = new Regex(@"(\d[0-9]{2}.\d[0-9]{2}.\d[0-9]{4}\s\d[0-9]{2}:\d[0-9]{2}:\d[0-9]{2})$");
test = r.IsMatch(str,0);

//output: test=false

Anyone knows why the String is not Matching with that regular expression?

You might need to double-escape the escapes (use two backslashes "\\" instead of one). — Reinstate Monica -- notmaynard
– Reinstate Monica -- notmaynard, Commented Jan 13, 2015 at 0:01
I have edited your title. Please see, "Should questions include “tags” in their titles?", where the consensus is "no, they should not". — John Saunders
– John Saunders, Commented Jan 13, 2015 at 0:28

Aran-Fey · Accepted Answer · 2015-01-13 00:03:42Z

3

\d[0-9]{2} matches three digits:

\d      first digit
[0-9]   second digit
{2}     causes the previous expression ([0-9]) to match again

If you remove all occurences of \d, your pattern should work. You should escape all dots . though, because right now they match any character, not just a ..

answered Jan 13, 2015 at 0:03

Aran-Fey

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Depa · Accepted Answer · 2015-01-13 00:10:34Z

0

As Rawing already said, the upper Regular expression is trying to match 3 digits instead of one. for everyone who want to know how the regular expression should look like:

@"(\d{2}.\d{2}.\d{4}\s\d{2}:\d{2}:\d{2})$"

Thats working, at least for me.

answered Jan 13, 2015 at 0:10

Depa

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1 Comment

test Over a year ago

You should have read his full answer and escaped your . characters.

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