How do you loop through your current directory and store files in an array? Bash shell script

Question

I am rather new to programming, and completely new to BASH. As described in the title, I am trying to loop through the current directory and store the files ending with .cpp into an array. I also am trying to create a second array which replaces the ".cpp" suffix with ".o" Whenever I try to compile I get "syntax error in conditional statement"

x=0
cwd=$(pwd)
for i in $cwd; do
  if [[ $i == *.cpp]]
  then
    cppfield[$x] = $i
    ofield[$x] = field[$x] | sed s/.cpp/.o/
    x=$((count+1))
  fi
done

Barmar · Accepted Answer · 2015-01-27 05:27:28Z

1

Use:

shopt -s nullglob # In case there are no matches
for i in *.cpp; do
    ...
done

In your code, you're just setting i to $cwd, not the files in the directory.

answered Jan 27, 2015 at 5:27

Barmar

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Comments

Neo1989 · Accepted Answer · 2015-01-27 05:29:17Z

1

I'm not sure what's your purpose of doing this. But if you just want to generate file name that replaces .cpp with .o, it can be done in a much easier way

for f in *.cpp
do
    echo ${f/.cpp/.o}
done

answered Jan 27, 2015 at 5:29

Neo1989

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1 Comment

Gordon Davisson Over a year ago

I'd use "${f%.cpp}.o" -- with the "%" (meaning "remove this from the end") instead of "/" (meaning replace the first occurrence of) in case the filename contains ".cpp" somewhere other than the end, and double-quotes in case it contains spaces or other shell metacharacters.

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