Laravel: Ajax pass selected option on change to controller

Question

I have a select box in my View. What I want to do is, when I select an option in the select box, it will update the view with data fetched from database. Below is a snippet of my attempted codes:

View.php

< script >
  $('#examId').on('change', function() {
    var optionSelected = $(this).find("option:selected");
    var examid = optionSelected.val();
    alert(examid);

    $.ajax({
        type: "post",
        url: "/admin/testresults/show",
        data: {
          id: examid
        }
        // data: $("#examId").val()
      })
      .done(function() {
        alert('im here');
      });
  }); < /script>

<form name="form1" method="post" action="testresults">
  <select name="examId" style="width:50%;" id="examId">
    <option value='non'>Select an exam...</option>
    <option value='1'>Foo1</option>
    <option value='2'>Foo2</option>
  </select>
  <input type="submit" />
</form>

if(isset($rows)){ 
  $i=1; 
  foreach ($rows as $row) { 
    print "
      <tr>
        <td>".$i."</td>
        <td>".$row->name." ".$row->last_name."</td>
        <td>".($result = ($row->result == 1) ? 'Pass' : 'Fail')."</td>
      </tr>
    ";
    $i++;
  }
}

Controller.php

public function showTestResults(){
  $examId = Input::get('id');
  $rows = TestResults::getExamNamebyID($examId);
  return  View::make('backend.admin.testResults.index')->with('rows', $rows);
}

Route.php

Route::post('testresults/show',array('as' => 'show','uses' => 'AdminController@showTestResults'));

Model.php

public static function getExamResults($examId){
    return DB::table('testresults')
        ->join('users', 'users.id', '=', 'testresults.userId')
        ->where('examId', $examId)
        ->groupBy('testresults.userId')
        ->get();
}

However, when i choose an option in the select box, I'm getting the following error:

POST http://localhost:8000/admin/testresults/show 500 (Internal Server Error)

What should I change? Is my concept correct? Thanks!

is your route correct ? do u hit on the showTestResults function ? — Kalhan
– Kalhan, Commented Jan 30, 2015 at 7:13
just return something in that controller like return "success"; and check you have get the same error or not ? dont forget to comment other things in the function. :) — Kalhan
– Kalhan, Commented Jan 30, 2015 at 7:16
@K.Toress i tried to change the controller to return a view called hello...did not work — Tommy Lee
– Tommy Lee, Commented Jan 30, 2015 at 7:22

Kalhan · Accepted Answer · 2015-01-30 08:29:21Z

2

seems like your routing is not correct, so please try this one,

change your view.php in to a blade file, to do that rename the view.php into view.blade.php

in your view file,

replace

<form name="form1" method="post" action="testresults">

with

Form::open(array('route' => 'show', 'name' => 'form1', 'id' => 'testForm', 'method' => 'POST'))

or

<form name="form1" method="post" action="{{ URL::route('show') }}" id="testForm">

in your js,

....
$.ajax({
    type: "post",
    url: $("#testForm").attr('action'),
    data: {
      id: examid
    }
    // data: $("#examId").val()
  })
  .done(function() {
    alert('im here');
});
....

edited Jan 30, 2015 at 8:29

answered Jan 30, 2015 at 8:17

Kalhan

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1 Comment

Tommy Lee Over a year ago

doesn't work, it says link_to_route() does not exist

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