send php post variable to url using javascript when button is clicked

Question

I have a php page which gets $page and $user using post method, I also have a button that i want, to open a URL in the same window using $page and $user variables when clicked, to use them with $_GET[] function. i want my URL be like:

http://www.test.com/test.php?page=$page&user=$user

my code is like this:

<?php
$page=$POST_['page'];
$user=$POST_['user'];
<?


<html>
<head>

function openurl() {
var user=<?php echo "$user";?>;
var page=<?php echo "$page";?>;
open('www.test.com/test.php?page='+page'&user='+user,'_self');

}

</head>
<body>

<button onclick="openurl()" type="button">open url</button>


</body>
</html>

If you want GET, then <a href="http://www.test.com/test.php?page=$page&user=$user" class="button">Open URL</a> with the appropriate CSS is the best way — mplungjan
– mplungjan, Commented Feb 5, 2015 at 10:24
I assume here's the mistake,<?php $page=$_POST['page']; $user=$_POST['user']; ?> — Pundit
– Pundit, Commented Feb 5, 2015 at 10:24
$POST_['page'] is wrong, use either $_POST['page'] for only post variable or $_REQUEST['page'] for both POST and GET variable — Bart Haalstra
– Bart Haalstra, Commented Feb 5, 2015 at 10:25
( I assume here's the mistake,<?php $page=$_POST['page']; $user=$_POST['user']; ?> ) but what is the right one? i need to put data from $page in to java variable. — Sina Nouri
– Sina Nouri, Commented Feb 5, 2015 at 10:27

mplungjan · Accepted Answer · 2015-02-05 12:20:35Z

1

There is no need for scripting at all

If you want GET:

<?php
$page=$GET_['page']; // should be sanitized and you can use REQUEST for either 
$user=$GET_['user'];
$parm = "page=".$page."&user=".$user;
?>
<a href="http://www.test.com/test.php?<?php echo $parm; ?>" class="button">Open URL</a>

If you need to post:

<form action="test.php" method="post">
<input type="hidden" name="page" value="<?php echo $page; ?>"/>
<input type="hidden" name="user" value="<?php echo $user; ?>"/>
<input type="submit" value="Open URL" />
</form>

edited Feb 5, 2015 at 12:20

answered Feb 5, 2015 at 10:35

mplungjan

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6 Comments

Sina Nouri Over a year ago

good idea, but when i click it the url become like "test.com/test.php?<? echo $parm ?>"

mplungjan Over a year ago

Then you need <?php instead of just <?

Sina Nouri Over a year ago

Thank you mplungjan <?php was the idea, it is working now, thanks a lot man.

Sina Nouri Over a year ago

another question, in post methode i think there is some problem with value="<$php echo $page; ?> cause it puts <$php echo $page; ?> in the text box. how can i fix it?

mplungjan Over a year ago

Your page has to be rendered by the pho engine so it must end on .php and be served from a server. View source and the must be no <?php ... ?> anywhere

|

wayzz · Accepted Answer · 2015-02-05 10:46:51Z

0

Change these lines:

<?php
$page=$POST_['page']; 
$user=$POST_['user']; 
<?

....

var user=<?php echo "$user";?>; 
var page=<?php echo "$page";?>; 
open('www.test.com/test.php?page='+page'&user='+user,'_self');

to this:

<?php
$page=$_POST['page']; //incorrect $_POST declaration
$user=$_POST['user']; //incorrect $_POST declaration
?> //php tag incorrectly closed

....

var user=<?php echo $user;?>; //echoing a variable not string (no need for quotes)
var page=<?php echo $page;?>; // echoing a variable not string (no need for quotes)
open('www.test.com/test.php?page='+page+'&user='+user,'_self'); // link was broken, forget to put '+' after page variable in link.

edited Feb 5, 2015 at 10:46

answered Feb 5, 2015 at 10:38

wayzz

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Comments

Federico Magnani · Accepted Answer · 2015-02-05 13:29:53Z

0

You can create a form and via Javascript just run YOURFORMNAME.submit();
Use href in javaScript to move to another location:

location.href="www.test.com/test.php?page='+page'&user='+user"

edited Feb 5, 2015 at 13:29

answered Feb 5, 2015 at 10:29

Federico Magnani

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1 Comment

Sina Nouri Over a year ago

thanks for your answer federico but i dont want to have form i can only have a button there in my page. i think the problem is data are not going into java var from php variable

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