How to run a block of code without blocking the application in Python?

Question

I have an application that allows you to use a Python startup script. I want to run one part of the code after the application is fully initialized, but there is no way to know this.

I used time.sleep() but then the application hangs till it executes that code. I also transferred the code to another file and used execfile but same result.

So basically I want something like this:

startup script:
    my code
    code to run 5 seconds later

What's the easiest way to achieve this? Do I have to use threading for this?

I think threading is the easiest way: stackoverflow.com/questions/16691576/… — ZZY
– ZZY, Commented Feb 6, 2015 at 4:10
@ZZY: I actually tried this an hour ago but it still blocks it when I use sleep in the other method. I don't know why that's not concerned by its own thread but I assume maybe the app itself is encapsulating everything to run in a single thread? — Joan Venge
– Joan Venge, Commented Feb 6, 2015 at 4:31
Maybe you can try executeInMainThreadWithResult or executeDeferred. I don't have Maya environment to test — ZZY
– ZZY, Commented Feb 6, 2015 at 8:06

dragon2fly · Accepted Answer · 2015-02-06 03:20:23Z

1

How about at the end of your startup script it writes to or creates a log file contains something like 'initiation complete'.

So another code will check if the file is created or the text is written after each x millisecond and then execute the rest of it.

answered Feb 6, 2015 at 3:20

dragon2fly

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3 Comments

Joan Venge Over a year ago

Thanks but who will run that code that checks for the file? Because if I start it and then that code hangs till the file is written, the app will still hang till then.

dragon2fly Over a year ago

@JoanVenge, you can throw the loop check for the log file to another thread or process, so the rest of your program will run without being blocked.

Joan Venge Over a year ago

Thanks I tried the thread thing but it didn't work. I will research the process thing.

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