Replacing multiple characters in Ruby string with one character

Question

I'm trying to replace all vowels in a string with a "*"

This is what I have at the moment

string = "alphabet"

string.gsub! "a", "*"
string.gsub! "e", "*"
string.gsub! "i", "*"
string.gsub! "o", "*"
string.gsub! "u", "*"

I want string to equal "*lph*b*t". What's the easiest way to do this?

Refer to the documentation at ruby-doc.org/core-2.2.0/String.html#method-i-gsub It provides an answer to exactly what you're asking — Fiddles
– Fiddles, Commented Feb 6, 2015 at 4:05

sawa · Accepted Answer · 2015-02-06 04:00:06Z

7

The easiest I can think of is:

string.tr!("aeiou", "*")

answered Feb 6, 2015 at 4:00

sawa

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Cary Swoveland · Accepted Answer · 2015-02-06 04:08:01Z

5

The other standard way is:

string = "alphabet"
string.gsub!(/[aeiou]/,'*')
  #=> "*lph*b*t" 
string
  #=> "*lph*b*t"

which you could also write

string.gsub!(/[aeiou]/) {'*'}

answered Feb 6, 2015 at 4:08

Cary Swoveland

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Comments

Parthiv · Accepted Answer · 2020-11-22 22:18:54Z

-1

In Javascript, Below is one of way to do this.

const vArr = 'aeiouy'.split('');

  const sArr = inputStr.split('');

  const binaryArray = sArr.map(i => {
    if(vArr.indexOf(i) > -1){
      return "0"; //I am trying to replace all vowels with zero
    } else {
      return i  //else replace with same char
    }
  })

  const resultStr = binaryArray.join('');

answered Nov 22, 2020 at 22:18

Parthiv

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