I am looking to remove parts of a string if it ends in a certain string.
An example would be to take this string: "[email protected]"
And remove the @2x.png so it looks like: "am.sunrise.ios"
How would I go about checking to see if the end of a string contains "@2x.png" and remove it?
You could check the lastIndexOf, and if it exists in the string, use substring to remove it:
String str = "[email protected]";
String search = "@2x.png";
int index = str.lastIndexOf(search);
if (index > 0) {
str = str.substring(0, index);
}
String.lastIndexOf can find the substring anywhere in the string, not just at the end. You should check str.endsWith(suffix) instead, and you can then inline the call to lastIndexOf.private static String removeSuffixIfExists(String key, String suffix) {
return key.endswith(suffix)
? key.substring(0, key.length() - suffix.length())
: key;
}
}
String suffix = "@2x.png";
String key = "[email protected]";
String output = removeSuffixIfExists(key, suffix);
Assuming you have a string initialized as String file = "[email protected]";.
if(file.endsWith("@2x.png"))
file = file.substring(0, file.lastIndexOf("@2x.png"));
The endsWith(String) method returns a boolean determining if the string has a certain suffix. Depending on that you can replace the string with a substring of itself starting with the first character and ending before the index of the character that you are trying to remove.
lastIndexOf is more correct since we need to remove the specified string only at the end. indexOf returns the first occurence of the specified string but in this case, we need the last occurence of that specified string. .endsWith("@2x.png") gives us the assurance that the lastIndexOf is actually @2x.png. @Pshemopublic static void main(String [] args){
String word = "[email protected]";
word = word.replace("@2x.png", "");
System.out.println(word);
}
"@[email protected]" and that should result to "@2x.png" not "" as this would tamper with the objective of the asker.
If you want to generally remove entire content of string from @ till end you can use
yourString = yourString.replaceAll("@.*","");
where @.* is regex (regular expression) representing substring starting with @ and having any character after it (represented by .) zero or more times (represented by *).
In case there will be no @xxx part your string will be unchanged.
If you want to change only this particular substring @2x.png (and not substirng like @3x.png) while making sure that it is placed at end of your string you can use
yourString = yourString.replaceAll("@2x\\.png$","");
where
$ represents end of string\\. represents . literal (we need to escape it since like shown earlier . is metacharacter representing any character)Since I was trying to do this on an ArrayList of items similarly styled I ended up using the following code:
for (int image = 0; image < IBImages.size(); image++) {
IBImages.set(image, IBImages.get(image).split("~")[0].split("@")[0].split(".png")[0]);
}
If I have a list of images with the names
[am.sunrise.ios.png, [email protected], [email protected], am.sunrise.ios~ipad.png, [email protected]]
This allows me to split the string into 2 parts. For example, "am.sunrise.ios~ipad.png" will be split into "am.sunrise.ios" and "~ipad.png" if I split on "~". I can just get the first part back by referencing [0]. Therefore I get what I'm looking for in one line of code.
Note that image is "am.sunrise.ios~ipad.png"
You could use String.split():
public static void main(String [] args){
String word = "[email protected]";
String[] parts = word.split("@");
if (parts.length == 2) {
System.out.println("looks like user@host...");
System.out.println("User: " + parts[0]);
System.out.println("Host: " + parts[1]);
}
}
Then you haven an array of Strings, where the first element contains the part before "@" and the second element the part after the "@".
Combining the answers 1 and 2:
String str = "[email protected]";
String search = "@2x.png";
if (str.endsWith(search)) {
str = str.substring(0, str.lastIndexOf(search));
}
substringandendsWithmethods from theStringclass@2x.pngor any substring which starts with@till end?