Separating a string using a regex pattern

Question

I am trying to get multiple variables from a single regex match.

std::string string_to_search = "abc def ghi";
std::regex pattern = "abc (.+) (.+)";
regex_search(string_to_search);
std::string segment1 = //assign to first [a-z]*
std::string segment2 = //assign to second [a-z]*

In ruby what I am trying to do is

case string_to_search

    when /\Aabc (.+) (.+)/
        segment1 = $1
        segment2 = $2
end

I don't know how to separate the string into separate variables based on the pattern. — chrisvj
– chrisvj, Commented Feb 16, 2015 at 1:48
Have you examined the functions exposed in <regex> and tried calling one with valid parameters, you know, to start? — Yakk - Adam Nevraumont
– Yakk - Adam Nevraumont, Commented Feb 16, 2015 at 1:57
I was looking at regex_iterator, but that would require me to create multiple regexes(regi?) which I guess I could do, but I was hoping wouldn't be necessary. — chrisvj
– chrisvj, Commented Feb 16, 2015 at 2:00

Marcin · Accepted Answer · 2015-02-16 01:59:52Z

1

The two groups can be obtained as follows:

std::string string_to_search = "abc def ghi";
std::regex pattern ("abc (.+) (.+)");
std::smatch base_match;


if (std::regex_match(string_to_search, base_match, pattern))
{
    std::cout << base_match[1] << endl; // def
    std::cout << base_match[2] << endl; // ghi
}

Description of regex_match and how to use it is here.

answered Feb 16, 2015 at 1:59

Marcin

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