Generic Operator Overloading in Swift

Question

I've been learning Swift and have a question about using Generics with Operator Overloading. This is my requirement:

Have a basic generic struct that implements generic matrix functionality, having three main parameters: row:Int, column:Int and array:[T].
Want to implement == operator, i.e. each parameter is ==.
Don't want to have to duplicate operator overload functions for each type.

It seems Swift isn't smart enough to allow me to write a generic operator overload function that references the generic array [T] without some workarounds?

I have read this post: [http://www.raywenderlich.com/80818/operator-overloading-in-swift-tutorial][1] and the solution given there seems surprisingly complicated.

I just wondered what the general consensus amongst the pro's here is? Sorry, I will post a code sample as an edit shortly.

Paul

So where's that code sample? lol...

Danny Bravo
– Danny Bravo

2015-05-06 21:26:55 +00:00
Commented May 6, 2015 at 21:26 — Danny Bravo
– Danny Bravo, Commented May 6, 2015 at 21:26

Manav Gabhawala · Accepted Answer · 2015-07-04 12:36:10Z

2

Here's how you can do that. Its very easy, you just need to ensure that T is Equatable.

struct Matrix<T> {
    // Definition goes here.
    var array = [T]()
}
func ==<T: Equatable>(lhs: Matrix<T>, rhs: Matrix<T>) -> Bool {
    return lhs.array == rhs.array 
}

edited Jul 4, 2015 at 12:36

answered Jul 4, 2015 at 9:43

Manav Gabhawala

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2 Comments

ABakerSmith Over a year ago

This currently doesn't work - if either array is empty, true will be returned regardless of whether the other array is empty or not. It would be better to write: return lhs.array == rhs.array.

Manav Gabhawala Over a year ago

Sorry I forgot about that my bad

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