So I have these statements in my code(there are many other lines but this is giving me trouble):
int *vector1;
if (vector1 == NULL)
{
}
When I try to run it it says "uninitialized local variable 'vector1' used" If I put "&vector1 == NULL" it doesn't complain but also doesn't work correctly.
I really don't understand why I am getting this error. I want it to do something if vector1 doesn't point to anything.
int *vector1 = NULL;
if (vector1 == NULL)
{
}
will work fine
int *vector1 = nullptr;
if (vector1 == nullptr)
{
}
Also works if you want to be a bit more up to date.
Pointers are not set to NULL by default. The answer why is here: Why aren't pointers initialized with NULL by default?
The warning uninitialized local variable 'vector1' used tells you that you're using vector1 even though you haven't initialized it. Therefore, its value might be anything.
Pointers (non-static ones) are not default-initialized to 0. They are initialized with random junk data.
If you want to initialize it with 0, NULL, or nullptr (all the same thing):
int *vector1 = 0; // or NULL, or nullptr.
