combine perl command inside the bash script

Question

Perl is excellent language to store command output to variable As I know bash isn’t support that

for example

my $value = qx(ls -ltr);
print $value;

it will print: ( example )

 -r-xr-xr-x 1 root     root          761 May 30  2014 ASon.conf
 -r-xr-xr-x 1 root     root          699 May 30  2014 ascpl
 drwxr-xr-x 2 root     root         4096 Feb 24 13:22 da
 drwx------ 2 root     root         4096 Feb 25 08:08 vm-root
 drwxr-x--- 2 root     root         4096 Feb 25 08:10 hspeoot
 -rw-r--r-- 1 root     root         2451 Feb 25 16:12 gry.txt
 -rw-r--r-- 1 root     root         3112 Mar  1 09:49 new.xml
 -rw-r--r-- 1 root     root        44893 Mar  1 12:13 SMports.xml
 -rwxr-xr-x 1 root     root          101 Mar  2 09:56 test
 -rwxr-xr-x 1 root     root    461340404 Mar  2 10:20 audin.log

the problem is that I write my code with bash and I want to use the Perl add value in my bash script

so is it possible to combine the following line in my bash script?

  my $value = qx(ls -ltr);

in way that when I print the value variable it will print the ls -ltr output

echo $value total 451052 -r-xr-xr-x 1 root root 761 May 30 2014 ASCBMon.conf -r-xr-xr-x 1 root root 699 May 30 2014 ascbmon.pl drwxr-xr-x 2 roog ( this print one long line ) not as I want , and cat $value not illegale — maihabunash
– maihabunash, Commented Mar 2, 2015 at 9:33
You need to put double quotes around "$value" when you echo it, otherwise the white space will be lost. — Tom Fenech
– Tom Fenech, Commented Mar 2, 2015 at 9:40
WOW its work - write your answer - so I will can vote and select your answer, — maihabunash
– maihabunash, Commented Mar 2, 2015 at 9:43
I'd suggest not mixing and matching between two scripting languages unless there's a particularly compelling need. That's a road to confusion and maintenance headaches. — Sobrique
– Sobrique, Commented Mar 2, 2015 at 10:43

Mat · Accepted Answer · 2015-03-02 09:43:47Z

4

You don't need perl for this, your shell can handle it:

value=$(ls -ltr)
echo "$value"

The quotes when you echo are important.

answered Mar 2, 2015 at 9:43

Mat

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ikegami · Accepted Answer · 2015-03-02 10:30:02Z

2

In Perl:

$var = `shell command`;
$var = qx( shell command );

In sh:

var=`shell command`
var=$( shell command )

answered Mar 2, 2015 at 10:30

ikegami

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