PHP merge array but only second array is random

Question

I have two array:

$divs = array('One','Two','Three','Four','Five','Six');
$ads = array ('Ad1', 'Ad2', 'Ad3');

I want merge like this:

$mix_divs = array_merge($divs, $reklama);

But, $divs must stay in same places and between this places I need to add random $ads array.

shuffle($ads);

Final input must be something like this:

$mix_divs = array('One','Two','Ad2','Three','Four','Ad3','Five','Six','Ad1');

or

 $mix_divs = array('Ad2','One','Two','Ad1','Three','Four','Five','Ad3','Six');

$ads must be random inserted.

How can I do that? Thanks

if you want the elements to stay in place, you're not looking for array_merge, you want to use array_splice to inject the $ads array elements. — castis
– castis, Commented Mar 2, 2015 at 21:38
You have not completely defined your question: Are there always six divs and three ads? Do you always want two divs between two ads? — KIKO Software
– KIKO Software, Commented Mar 2, 2015 at 21:53

Tommaso Bertoni · Accepted Answer · 2015-03-02 21:57:26Z

1

You just insert each ad in a random position in divs:

$divs = array('One','Two','Three','Four','Five','Six');
$ads = array ('Ad1', 'Ad2', 'Ad3');

$newArray = array_merge($divs);
for ($i = 0; $i < count($ads); $i++) {
    $position = rand(0, count($newArray));
    array_splice($newArray, $position, 0, $ads[$i]);
}

I just tried to print_r($newArray) and it gave me:

Array
(
    [0] => One
    [1] => Two
    [2] => Three
    [3] => Ad2
    [4] => Four
    [5] => Ad1
    [6] => Five
    [7] => Ad3
    [8] => Six
)

answered Mar 2, 2015 at 21:57

Tommaso Bertoni

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Comments

mhall · Accepted Answer · 2015-03-02 22:06:47Z

1

$divs = array('One','Two','Three','Four','Five','Six');
$ads  = array('Ad1', 'Ad2', 'Ad3');

shuffle($ads);
while ($ads) array_splice($divs, array_rand($divs), 0, array_pop($ads));

print_r($divs);

Output:

Array
(
    [0] => Ad1
    [1] => One
    [2] => Two
    [3] => Ad3
    [4] => Three
    [5] => Four
    [6] => Five
    [7] => Ad2
    [8] => Six
)

answered Mar 2, 2015 at 22:06

mhall

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