JavaScript - Bring multiple variables from PHP

Question

I have the following PHP code. It creates multiple variables using $a; for example: $numtoken1.

$sql ="SELECT token, dispositivo FROM dispositivos WHERE idcliente=1";
mysql_select_db('localiza');
$retval = mysql_query( $sql, $conn );
$num_rows = mysql_num_rows($retval);

while($row = mysql_fetch_array($retval, MYSQL_BOTH))
{
    $numtoken['$a']=$row['token'];
    $numdispositivo['$a']=$row['dispositivo'];
    $a=$a++;
}

Using JavaScript, I want to call all the PHP variables using that code, but it only get the last $a number.

My question is: In a JavaScript loop, how can I dynamically insert the value for $a? Because in the above PHP, I have multiple values for $a.

var accessToken = "<?= $numtoken['$a']; ?>"a;
var deviceID = "<?= $numdispositivo['$a']; ?>";

your while loop keeps overwritting the data... do var_dump($numtoken) you will see... I think you'd want to remove the quotes from that $a inside the brakets — Salketer
– Salketer, Commented Mar 6, 2015 at 15:13
k, but the problem is I have in php numtoken1,numtoken2,numtoken13... so I need if the javascript var accessToken = "<?= $numtoken['$a']; ?>"; insert automacally the $a value but that command "<?= $numtoken['$a']; ?>" is a php command, How can I change the $a in javascript and send it to php? – — Roberto Bahia
– Roberto Bahia, Commented Mar 6, 2015 at 16:03

Richard Lovern · Accepted Answer · 2015-03-06 15:12:13Z

2

I suggest JSON:



    var accesstoken = JSON.parse("<?= json_encode($numtoken); ?>");
    var deviceID = JSON.parse("<?= json_encode($numdispositivo); ?>");

answered Mar 6, 2015 at 15:12

Richard Lovern

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2 Comments

Roberto Bahia Over a year ago

ok, but the problem is I have in php numtoken1,numtoken2,numtoken13... so I need if the javascript var accessToken = "<?= $numtoken['$a']; ?>"; insert automacally the $a value but that command "<?= $numtoken['$a']; ?>" is a php command, How can I change the $a in javascript and send it to php?

Richard Lovern Over a year ago

@RobertoBahia Using PHP to echo the JSON encoded sting into your javascript is a one way trick. If your issue is getting information from javascript back to PHP, you are going to need to look into making an AJAX call to a PHP processing script.

pxslip · Accepted Answer · 2015-03-13 13:10:51Z

0

So the first thing I noticed when looking at this is that you are wrapping $a in single quotes (') instead of double quotes (") this means that instead of evaluating $a the key in the array will be the string "$a", so you'll be overwriting the value in each iteration of the while loop. See - http://php.net/manual/en/language.types.string.php#language.types.string.parsing for more info.

That being said the actual answer to your question varies, but the simplest method might be to use the json_encode function to convert your arrays into json objects.

var accessTokenArr = <?php print json_encode($numtoken); ?>
var deviceIdArr = <?php print json_encode($numdispositivo); ?>

Then you can iterate over the values in those arrays and do whatever you want to with the values. Fair warning - you may need to tweak that code a little as I haven't tested it to make sure it plays nicely.

edited Mar 13, 2015 at 13:10

answered Mar 6, 2015 at 15:30

pxslip

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2 Comments

Roberto Bahia Over a year ago

So I bring hte information with that command: var deviceIdArr = <?php print json_encode($numdispositivo); ?>; I tried use subtr to get one value of array but is not possible. I tried too usinge var a = 0; var deviceID1=deviceIdArr[a]; but can't get the value. you know how can I get the fvalues from json_encode?

pxslip Over a year ago

It's difficult to say as I don't know what the structure of your data is. What errors are you getting in the console? You can also see what the data looks like by doing console.log(accessTokenArr); or console.log(deviceIdArr);

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