Crontab - Shell Script

Question

I have the following command in my crontab:

* * * * * root /home/amith/m.sh >dev/null 2>&1

where m.sh consists of:

#!/bin/sh
curl -0 "http://www.google.com" > /home/amith/Desktop/h2

but the command in shell script is not executing at all. Can anyone please tell me the solution?

is m.sh executable ? Also I would try with 1 * * * * instead of all *. — tgo
– tgo, Commented Mar 8, 2015 at 7:39

klerk · Accepted Answer · 2015-03-08 11:33:19Z

1

First be sure that your script /home/amith/m.sh is running correctly! Your crontab entry is wrong you dont need root before script. Also your redirection to /dev/null is not good you are missing / before dev

You can set env varibale for SHELL in crontab with this

crontab -e
SHELL=/bin/sh

Then add your script:

* * * * * /home/amith/m.sh >/dev/null 2>&1

answered Mar 8, 2015 at 11:33

klerk

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colintobing · Accepted Answer · 2015-03-08 08:58:01Z

0

* * * * * cd /full/path; sh m.sh;

First, change the directory into your file location (use cd). Then, bash it with sh command. Change * * * * * with the time schedule. To run the file every minute * * * * * To run every hour (1:00, 2:00, 3:00 and so on) use 00 * * * * To run everyday at 6 AM use 00 06 * * * To run the file on 9th March at 6 AM use 00 06 09 03 * The structure is minute hour date month day of week If you want to schedule it every Monday at 06 AM use this 00 06 * * 1 See this link http://www.pantz.org/software/cron/croninfo.html

edited Mar 8, 2015 at 8:58

answered Mar 8, 2015 at 7:40

colintobing

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