How can I find the arguments in a php function?

Question

I know how to check with func_num_args for the number of arguments for a function, but how can I get these arguments inside the php function:

<?php
function test() {
        echo func_num_args(); //returns 2
        echo $argv[1]; //this doesn't work
}

test("aa","bb");

?>

s-ol · Accepted Answer · 2015-03-08 21:31:14Z

2

You can call func_get_args() to obtain the array of arguments passed to the function.

For your example, simply add

$args = func_get_args();

And it should work as intended.

There also is func_get_arg, which returns a single argument:

echo func_get_arg(1); // prints second argument

answered Mar 8, 2015 at 21:31

s-ol

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Comments

Rizier123 · Accepted Answer · 2015-03-08 21:35:01Z

2

For PHP 5.6+ you can use: ... like this:

function xy(...$args) {

    foreach($args as $arg)
        echo $arg . "<br />";

}

answered Mar 8, 2015 at 21:35

Rizier123

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