delete zero after single character using regex

Question

i have a string with a single character and a digit, for eg J0. I have to write an expression to remove 0 and keep only that single character.

I did the same way, but that deletes all. I want to delete only 0 and keep J as it is. eg : J0 to J. — Shaik Mujahid Ali
– Shaik Mujahid Ali, Commented Mar 10, 2015 at 11:39
what do you mean by it deletes all? Could you provide an exact example? or replace 0 with empty string. — Avinash Raj
– Avinash Raj, Commented Mar 10, 2015 at 11:40
I have used like this name.replaceAll("([A-Z][0-9])","") and my output is blank. what i want is when i give J0 i need J. J0 is my input string. — Shaik Mujahid Ali
– Shaik Mujahid Ali, Commented Mar 10, 2015 at 11:42
Why dont you use just name.replaceAll("([0-9])","") ? [A-Z] will replace chars from A to Z too, that's including J, for instance — Danilo Gomes
– Danilo Gomes, Commented Mar 10, 2015 at 11:52

Avinash Raj · Accepted Answer · 2015-03-10 11:43:57Z

1

Use a positive lookbehind assertion or capturing group to replace a digit which exists next to an uppercase letter with empty string.

name.replaceAll("(?<=[A-Z])[0-9]", "");

OR

name.replaceAll("([A-Z])[0-9]", "$1");

answered Mar 10, 2015 at 11:43

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

or name.replaceAll("[0-9]$", "");

kvivek · Accepted Answer · 2015-03-10 11:44:35Z

0

I tried in Python using regular expression With your assumption that you have a string with a single character and a digit, for eg J0

>>> import re
>>> x = re.search('(\w)\d', 'j0')
>>> x.groups()
('j',)
>>> x.groups()[0]
'j'

You can use the pattern (\w)\d

answered Mar 10, 2015 at 11:44

kvivek

3,6011 gold badge17 silver badges17 bronze badges