I have a function f(a,b,c) waiting for 3 int. I have a list t = list(1,2,3) that i want to input to f : f(t). But it doesn't work. What is the easiest way to do it.
EDIT : t = list('1','2','3')
Thank you
0
Add a comment
|
3 Answers
You need to unpack the values present in list t.
f(*t)
Example:
>>> def f(a,b,c):
print(a,b,c)
>>> t = [1,2,3]
>>> f(*t)
1 2 3
OR
>>> def f(a,b,c):
print(a,b,c)
>>> t = ['1','2','3']
>>> f(*map(int,t))
1 2 3
3 Comments
The Answer
What if a,b,c are strings and i want to change them in the same time to integers ?
Eduard Luca
Will the code break if the list has only 2 items (and
c doesn't have a default value)? Just curious.
Avinash Raj
yep, because the defined function needs exactly three parameters. You could set the default value of c like
def f(a,b,c=0):You will have to pass the values as follows:
f(t[0], t[1], t[2])
Comments
You can call the function like this:
f(t[0],t[1],t[2])
Cheers!
