I want to pass arguments to a script in the form
./myscript.sh -r [1,4] -p [10,20,30]
where in myscript.sh if I do:
echo $@
But I'm getting the output as
-r 1 4 -p 1 2 3
How do I get output in the form of
-r [1,4] -p [10,20,30]
I'm using Ubuntu 12.04 and bash version 4.2.37
You have files named 1 2 3 & 4 in your working directory.
./myscript.sh -r "[1,4]" -p "[10,20,30]"
[1,4] gets expanded by bash to filenames named 1 or , or 4 (whichever are actually present on your system).
Similarly, [10,20,30] gets expanded to filenames named 1 or 0 or , or 2 or 3.
On similar note, you should also change echo $@ to echo "$@"
On another note, if you really want to distinguish between the arguments, use printf '%s\n' "$@" instead of just echo "$@".
printf '%s\n' "$@" is still giving me the same output. So does echo "$@". I want the arguments to be read as is without adding any more quotes.
[1,4] and [10,20,30]) no longer match them. The safe way is to use more quotes when you call your script.
[1,4] will get expanded to 1 4 as read by script. "[1,4]" will be read as [1,4] by the script. "\"[1,4]\"" will get read as "[1,4]". Second option is what you need.You can turn off filename expansion
set -f
./myscript.sh -r [1,4] -p [10,20,30]
Don't expect other users to want to do this, if you share your script.
The best answer is anishane's: just quote the arguments
./myscript.sh -r "[1,4]" -p "[10,20,30]"
You can just the escape the brackets[]. Like this,
./verify.sh -r \[1,4\] -p \[10,20,30\]
You can print this using the echo "$@"
./test1.bash -r [1,4] -p [10,20,30]output:-r [1,4] -p [10,20,30]zsh,csh,shandbashinterpreter and they all returned your desired output...