Create Android Selector in code

Question

I have a drawable called "XYZ"

<item android:state_pressed="false">
    <shape xmlns:android="http://schemas.android.com/apk/res/android">
        <solid android:color="@color/highlightpen_blue" />

        <padding android:bottom="7dp" android:left="10dp" android:right="10dp" android:top="7dp" />

        <corners android:bottomLeftRadius="5dp" android:bottomRightRadius="5dp" android:topLeftRadius="5dp" android:topRightRadius="5dp" />
    </shape>
</item>

in a button android:background="@drawable/XYZ"

i just want to create XYZ in code purely to change @color/highlightpen_blue

cruelcage · Accepted Answer · 2015-03-15 03:06:30Z

1

Like Fahim's answer,but some difference.

StateListDrawable states = (StateListDrawable) btn.getBackground();
GradientDrawable bgShape = (GradientDrawable) states.getCurrent();
bgShape.setColor(Color.BLACK);

answered Mar 15, 2015 at 3:06

cruelcage

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Fahim · Accepted Answer · 2015-03-15 01:41:09Z

0

You can do it with the of GradientDrawable

GradientDrawable background = (GradientDrawable) titleTextView.getBackground();
 background.setColor(getResources().getColor(R.color.some_color))

answered Mar 15, 2015 at 1:41

Fahim

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2 Comments

DayDayHappy Over a year ago

thanks but it should not work because the Background is not a GradientDrawable, but Selector. I actually want the button with some solid color with round corner

Fahim Over a year ago

@DayDayHappy this will change the color of <shape> tag in the xml at runtime and it will keep the round corner, what you are doing in the xml

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