Send custom data with dropzone.js on each File Upload

Question

I am using dropzone in my Code Igniter Project.

With every drag of a file, dropzone creates an ajax request and my files is getting stored on the server too. But now, my requirement is that I want to send additional data (DYNAMIC) alongside the file. With the use of params, Only static datas can be sent, but the data I want to send will be changing everytime.

This is how my code looks:

<script>
 Dropzone.autoDiscover = false;
  Dropzone.options.attachment = {
        init: function(){
          this.on('removedfile',function(file){
            // console.log('akjsdhaksj');
            var fileName = file.name;
            $.ajax({
              type: 'POST',
              url: "<?php echo BASE_URL.'index.php/admin/mail_actions/deleteFile' ?>",
              data: "id="+fileName,
              dataType: 'html'
            });
          });
        },
        // params: {
        // customerFolder: $('#toValue').substr(0, toValue.indexOf('@')),
        // },
        dictDefaultMessage:"Click / Drop here to upload files",
        addRemoveLinks: true,
        dictRemoveFile:"Remove",
        maxFiles:3,
        maxFilesize:8,
  }

$(function(){

  var uploadFilePath = "<?php echo BASE_URL.'index.php/admin/mail_actions/uploadFile' ?>";
  var myDropzone     = new Dropzone("div#attachment", { url: uploadFilePath});

});
</script>

Anyway I can achieve it?

Jesper · Accepted Answer · 2019-04-17 11:21:51Z

133

I got it. This is what I had to use

myDropzone.on('sending', function(file, xhr, formData){
    formData.append('userName', 'bob');
});

edited Apr 17, 2019 at 11:21

Jesper

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answered Mar 16, 2015 at 10:04

Abhinav

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12 Comments

Shiva Over a year ago

i tried using this but no luck..and where to add this code? in init ?

Abhinav Over a year ago

How have you defined your dropzone? Without a snippet its hard to answer. Create a fiddle

Shiva Over a year ago

it is sending but not understanding the way it is sending.Content-Disposition: form-data; name="name" sss Content-Disposition: form-data; name="description"

Abhinav Over a year ago

Try remove the sending method when creating the dropzone instance, and bind the sending method using on

Shiva Over a year ago

what is username and bob ? is those are form fields ?

|

Stan · Accepted Answer · 2016-05-20 13:26:41Z

30

Abhinav has the right and working answer I only want to give a second option to use it in the options object (for example if you have multiple Dropzone sections on one page.)

myDropzone.options.dropzoneDivID = {
    sending: function(file, xhr, formData){
        formData.append('userName', 'Bob');
    }
};

answered May 20, 2016 at 13:26

Stan

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2 Comments

Bron Davies Over a year ago

I gave your answer an upvote since it shows that there is more than one way to implement this feature

Abdan Syakuro Over a year ago

how do you put variable outside dropzone to the form data append?

Achim Koellner · Accepted Answer · 2017-02-26 09:21:02Z

13

In case you have a nested payload object - e.g. to add a name to your file and your api only accepts something like this

{
    someParameter: {
        image: <my-upload-file>,
        name: 'Bob'
    }
}

your dropzone setup would look like this

var myDropzone     = new Dropzone("div#attachment", { 
    url: uploadFilePath,
    paramName: 'someParameter[image]'
});

myDropzone.on('sending', function(file, xhr, formData){
    formData.append('someParameter[image]', file);
    formData.append('someParameter[userName]', 'bob');
});

I only added this as there was no example for nested parameters documented since now.

answered Feb 26, 2017 at 9:21

Achim Koellner

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Comments

Tarek Adra · Accepted Answer · 2020-08-19 19:54:53Z

2

i was using JQuery and this is how worked for me :

           $("#dZUpload").dropzone({
                url: "ajax/upload_img_ben.php",
                success: function (file, response) {
                    var imgName = response;
                    file.previewElement.classList.add("dz-success");
                    console.log("Successfully uploaded :" + imgName);
                },
                error: function (file, response) {
                    file.previewElement.classList.add("dz-error");
                },
                sending: function(file, xhr, formData){
                    formData.append('id', '5');
                }
            });

answered Aug 19, 2020 at 19:54

Tarek Adra

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