org.json.JSONObject exception on a valid json string

Question

I have the following code:

try {
    JSONObject json = new JSONObject(data);
    ...
} catch(JSONException ex) {
    if(LOGS_ON) Log.e(TAG, "Could not save data.", ex);
}

It throws an exception, although the json string passed in is pretty valid. The exception is the following:

org.json.JSONException: Value {"ShopId3Digit":"ww0","ServerTime":1426695017191,"SMSTelephone":"2104851130","SendPODAgain":true,"SendLocationAgain":true,"IsHUB":false,"AllowReceiptsAndDeliveries":true} of type java.lang.String cannot be converted to JSONObject

Do you see something wrong with the json data I'm passing in?

BTW this is the string as seen in Eclipse watch:

"{\"ShopId3Digit\":\"ww0\",\"ServerTime\":1426695017191,\"SMSTelephone\":\"2104851130\",\"SendPODAgain\":true,\"SendLocationAgain\":true,\"IsHUB\":false,\"AllowReceiptsAndDeliveries\":true}"

try using JSONParser

snaikar
– snaikar

2015-03-18 16:42:00 +00:00
Commented Mar 18, 2015 at 16:42 — snaikar
– snaikar, Commented Mar 18, 2015 at 16:42

godfatherofpolka · Accepted Answer · 2015-03-18 17:03:23Z

1

Here's a working version

import org.json.JSONException;
import org.json.JSONObject;

public class Test {
  public static void main(String[] args) {
    String data = "{\"ShopId3Digit\":\"ww0\",\"ServerTime\":1426695017191,\"SMSTelephone\":\"2104851130\",\"SendPODAgain\":true,\"SendLocationAgain\":true,\"IsHUB\":false,\"AllowReceiptsAndDeliveries\":true}";

    try {
      JSONObject json = new JSONObject(data);
      System.out.println("Success: json = ");
      System.out.println(json.toString(2));
    } catch(JSONException ex) {
      System.out.println("Error: " + ex);
    }
  }   
}

(using the most recent version available at https://github.com/douglascrockford/JSON-java). I have tested this code, it compiles and successfully outputs

Success: json = 
{
  "IsHUB": false,
  "SMSTelephone": "2104851130",
  "AllowReceiptsAndDeliveries": true,
  "SendPODAgain": true,
  "SendLocationAgain": true,
  "ShopId3Digit": "ww0",
  "ServerTime": 1426695017191
}

Therefore, the error seems to be not with the json data.

edited Mar 18, 2015 at 17:03

answered Mar 18, 2015 at 16:54

godfatherofpolka

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4 Comments

alfoks Over a year ago

I'm using the version that comes with Android SDK. I even tested with the string hard-coded as you did, but I'll recheck tomorrow. I might forgot something.

alfoks Over a year ago

Something else is happening. When I try it hard-coded it works.

godfatherofpolka Over a year ago

@alfoks Please provide more code and information on how you obtain the json data? Can you create a minimal, self-contained example in which the error occurs?

alfoks Over a year ago

It was my mistake after all. I obtain the data from a .NET program through Newtonsoft serializer. By mistake I was serializing the already serialized object resulting in just a string. The starting and ending quotes in the watch in Eclipse are actually part of the value.

alfoks · Accepted Answer · 2015-03-19 09:47:06Z

0

It was my mistake after all. I obtain the data from a .NET program through Newtonsoft serializer. By mistake I was serializing the already serialized object resulting in just a string. The starting and ending quotes in the watch in Eclipse are actually part of the value.

Thank you godfatherofpolka for the effort you went through.

answered Mar 19, 2015 at 9:47

alfoks

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