How to search for version no python:
Build Host : iox-lux-013
Version : 3.2.8.08I sample
I tried:
import re
p=re.compile("Version.*: (.*?) ")
list=p.findall(s)
for i in list:
print i
works good
but not for:
Version : 3.2.8.08I
doesnt work :/
Use \S+ to match one or more non-space characters.
p = re.compile(r"Version\s*:\s*(\d+(?:\.\d+)*[A-Z]\b)")
\s* matches zero or more spaces , so you don't need to use .* before :
Example:
>>> s = '''Build Host : iox-lux-013
Version : 3.2.8.08I sample
Version : 3.2.8.08I'''
re.findall(r"Version\s*:\s*(\d+(?:\.\d+)*[A-Z]\b)", s)
['3.2.8.08I', '3.2.8.08I']
import re
s = '''Build Host : iox-lux-013
Version : 3.2.8.08I sample
Version : 3.2.8.08I '''
f = re.findall(r"Version\s+:( [0-9]+.[0-9]+.[0-9]+.[0-9]+[A-Z])(\s[A-Z])*", s)
print(f)
Use \S+ to match one or more non-space characters.
( [0-9]+.[0-9]+.[0-9]+.[0-9]+[A-Z])
this group will check for the version numbering. (\s[A-Z])* will check whether the string + space is availabl;e or not
* -> 0 or more
sdefined?