Java Date format. String to date

Question

I have a String that contains a date.

I'm trying to do so but it gives me an error.

java.text.ParseException: Unparseable date: "Fri Mar 20 20:44:49 CET 2015" (at offset 0)
at java.text.DateFormat.parse(DateFormat.java:626)

I'm trying this.

String fechaFestivo = c.getString(1);//Fri Mar 20 20:44:49 CET 2015

SimpleDateFormat format = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy");
Date date = format.parse(fechaFestivo);

Try this DateFormat format = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy", Locale.ENGLISH); — Skizo-ozᴉʞS ツ
– Skizo-ozᴉʞS ツ, Commented Mar 24, 2015 at 10:50
I tried your solution (as well as the one of @Skizo) and both are working for me (only change is that I hardcoded Fri Mar 20 20:44:49 CET 2015). Are you sure about fechaFestivo string ? — Gaëtan Maisse
– Gaëtan Maisse, Commented Mar 24, 2015 at 10:59

nicopico · Accepted Answer · 2015-03-24 10:55:36Z

3

Your SimpleDateFormat is using the default locale, which may not be English. In that case, the abbreviated name of the day will not be recognized.

Make sure to use the correct locale with this constructor:

SimpleDateFormat format = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy", Locale.US);

answered Mar 24, 2015 at 10:55

nicopico

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Skizo-ozᴉʞS ツ · Accepted Answer · 2015-03-24 10:53:44Z

1

Try to replace your SimpleDateFormat for DateFormat, something like that :

String fechaFestivo = c.getString(1); //Fri Mar 20 20:44:49 CET 2015

DateFormat format = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy", Locale.ENGLISH);
Date date = format.parse(fechaFestivo);

answered Mar 24, 2015 at 10:53

Skizo-ozᴉʞS ツ

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Arun Kumar · Accepted Answer · 2015-03-24 10:54:08Z

0

Use "EEE MMM dd HH:mm:ss zzz yyyy"

answered Mar 24, 2015 at 10:54

Arun Kumar

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