How to exit powershell script if window name exists?

Question

I can get a list of current open windows like this:

Get-Process | where {$_.mainWindowTitle} | format-table mainWindowTitle

How do I write proper syntax to loop and check if Window Name exists and then exit?

Below is the logic I would like to execute:

# BASIC-esque CONDITIONAL LOGIC
# FILENAME: CheckWindowName.ps1

Get-Process | where {$_.mainWindowTitle} | format-table mainWindowTitle

# LOOP START - Loop through $_.mainWindowTitle / mainWindowTitle

If $_.mainWindowTitle CONTAINS "*notepad*" Then
    Exit #break script
Else
    Echo "Hello World! There are no instances of notepad open"
End If

# LOOP END

Matt · Accepted Answer · 2015-03-25 03:27:05Z

2

Get-Process | where {$_.mainWindowTitle} | ForEach {
    #iterates through processes here. each one can be referenced by $_
}

A basic introduction into how ForEach-Object works can be found on TechNet

edited Mar 25, 2015 at 3:27

Matt

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answered Mar 25, 2015 at 1:03

Jon Tirjan

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2 Comments

Level1Coder Over a year ago

tks, can you expand on the #iterates through processes here. each one can be referenced by $_ logic?

Jon Tirjan Over a year ago

Please research "PowerShell foreach loop" to learn more. For now, just run this: if (ps notepad -ErrorAction SilentlyContinue) {'Notepad is open'}

user3788641 · Accepted Answer · 2015-03-25 04:43:56Z

1

Try to use -like instead of contains. It worked for me.

Below is the example:

PS C:\windows\system32> Get-Process | where {$_.mainWindowTitle -like "notepad" }

Handles NPM(K) PM(K) WS(K) VM(M) CPU(s) Id ProcessName ------- ------ ----- ----- ----- ------ -- ----------- 71 7 1516 6760 95 0.23 6328 notepad 71 7 1516 6676 95 0.11 7212 notepad 68 7 1472 2808 94 8.14 7364 notepad 73 7 1540 1568 95 0.48 8640 notepad 74 8 1820 1672 160 9.41 8884 notepad

answered Mar 25, 2015 at 4:43

user3788641

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1 Comment

user3788641 Over a year ago

use wild card * in front of notepad and after notepad.

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