Regex to extract Domain name based on Path

Question

I need a regex to extract server names from below json based on the path. So ideally I should get server1 & server2 the string between https & /upload/image/app as output and ignore the youtube url.

{
    "url1" : "https://server1/upload/image/app/test1.jpg",
    "video" : "https://www.youtube.com/watch?v=K7QaD3l1yQA",
    "type" : "youtube",
    "url2" : "https://server2/upload/image/app/test2.jpg"
}

Tried this, but i know this wont work:

https://(.*?)/upload/image/app

What is the question here? You said it yourself: use a regex to extract the informaiton from the string you get when iterating over the entries... — arkascha
– arkascha, Commented Mar 27, 2015 at 13:32
Not able to formulate a regex that does this, the youtube url is making it difficult — Farhan
– Farhan, Commented Mar 27, 2015 at 13:35
In what programming language/environment are you planning to do this? — C3roe
– C3roe, Commented Mar 27, 2015 at 13:35
Then post your attempts so far and point out what is not working. How else should we help with that otherwise? — arkascha
– arkascha, Commented Mar 27, 2015 at 13:36

Phate01 · Accepted Answer · 2015-03-27 13:37:57Z

1

^(?:http|https)\:\/\/(.*?)\/(?:.*?)$

This should do the trick. Examples:

<?php
preg_match("/^(?:http|https)\:\/\/(.*?)\/(?:.*?)$/", "https://server1/upload/image/app/test1.jpg", $matches);
echo $matches[1]; //server1
?>

It's not so difficult to work with regex, I suggest you to start learining at least basics because they may be useful

answered Mar 27, 2015 at 13:37

Phate01

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8 Comments

Farhan Over a year ago

My input is not a single URL but the whole json

Phate01 Over a year ago

I'm not here to do your homework. You asked for a regex and now you have it

Farhan Over a year ago

Well the regex changes if you use single url vs the whole json, thanks for the help anyways.

Phate01 Over a year ago

Can't you parse the JSON and then match for all elements?

JNYRanger Over a year ago

@Farhan Sounds like a terrible idea. Don't take lazy shortcuts like this. This leads to bad code and maintenance issues down the road. Also, regular expression engines are NOT parsers, so don't use them as such. Instead you can combine the technologies to reach your goal.

|

Community · Accepted Answer · 2017-05-23 11:50:53Z

0

You can try with something like that:

^.*http.*//(\S+)/upload/ima.*

Edit: including a JAVA example:

Pattern p = Pattern.compile("^.*http.*//(\\S+)/upload/ima.*");
Matcher m = p.matcher(nextLine);

if (m.find()) {
    System.out.println(m.group(1));
}

Check: Using Regular Expressions to Extract a Value in Java

edited May 23, 2017 at 11:50

CommunityBot

11 silver badge

answered Mar 27, 2015 at 13:53

Le Funes

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