loopVar=1;
alert('#imgAvatar'+parseInt(loopVar)+1);
gives me #imgAvatar11
While
alert(parseInt(loopVar)+1);
gives me 2
How can I get #imgAvatar2 ?
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Might be you want this stackoverflow.com/questions/29346771/…Sadikhasan– Sadikhasan2015-03-30 13:04:31 +00:00Commented Mar 30, 2015 at 13:04
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4 Answers
Your loopVar is already an integer (notice you haven't put it in quotes, so it is integer). No need to do parseInt.
Use it:
loopVar=1;
alert('#imgAvatar'+(loopVar+1));
FIDDLE: http://jsfiddle.net/15bucsy5/
It's because you're adding to the string #imgAvatar so the numbers will be converted to strings as well, and it's really read as "#imgAvatar" + "1" + "1".
Use parentheses to create a block where the numbers can be added up before they are added to the string
var loopVar = 1;
alert( '#imgAvatar' + ( (+loopVar) + 1 ) );
Whenever the addition operator is used with a string, all other values will be converted to strings as well
Thats the trouble:
"foo" + 1 + 1 == "foo1"+1 == "foo11";
Thats the answer
alert( '#imgAvatar' + ( parseInt(loopVar) + 1) ) );
P.S. jsfiddle: https://jsfiddle.net/emtLfv9r/
If not worknig - show to us your html.
4 Comments
David
sorry but not working for me. Only Sadikhasan version worked fine.
Legendary
it because i added jQuery selector, cos i think, that u wanna select that. nvm, glad for u
David
Guys I Apologize, my loopVar was char probably.
Legendary
oh, so in that way - right ans is ('#imgAvatar' + ( parseInt(loopVar)+1) )
You need to add parenthesis () for priority to evaluate add loopVar first. If your variable contains numeric value then do not need to apply parseInt function.
loopVar = "1";
alert('#imgAvatar'+(parseInt(loopVar)+1));
OR
loopVar = 1;
alert('#imgAvatar'+ (loopVar+1) );
