I have the string "22" and I'm getting 3 as length;
I used .trim()
What else could be a reason for this?
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4You'll have to show us your code, because as stated, it's not possible.CPerkins– CPerkins2010-05-30 16:26:57 +00:00Commented May 30, 2010 at 16:26
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3 Answers
You should be giving us code that demonstrates the problem, but my guess is you did something like this:
String str = "22 ";
str.trim();
System.out.println(str.length());
But str.trim() doesn't change str (as Strings are immutable). Instead it returns a new String trimmed. So you need something like this:
String str = "22 ";
str = str.trim();
System.out.println(str.length());
1 Comment
Gordon Gustafson
5 minute response time?!?! Come on guys, we can do better than that... ;)
Try this:
System.out.println(java.util.Arrays.toString(theString.toCharArray()));
This dumps the char[] version of the String, so we can perhaps see if it contains anything funny.
answered May 30, 2010 at 16:28
polygenelubricants
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2 Comments
Mark Peters
+1 It's a good diagnostic tool even if it wasn't needed this time.
Henry A.
Didn't even have the same problem is OP but this really helped figure out that the string was using ANSI escape codes. +1
since i found a reason while formulating the question, im gonna answer myself..
If the string was created by .substring or split, the whole string is saved plus the position and length of the substring.
this apparently cant be trimmed (was " 22")
1 Comment
Mark Peters
length() does not return the length of the backing array, and it should be able to be trimmed. See my answer.