java.net.MalformedURLException: Protocol not found. Reason?

Question

I am using this function :

public void testing(String xml) throws ParserConfigurationException, SAXException, IOException{
        Log.d("TAG"," root.getNodeName()");
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();

        Document document = builder.parse(xml);

        //document.getDocumentElement().normalize();
        //Element root = document.getDocumentElement();
        //Log.d("TAG", root.getNodeName());
        Log.d("TAG"," root.getNodeName()");

    }

And I am calling this function like this :

testing(responseText)

Where response text is this:

<?xml version='1.0' encoding='UTF-8'?>
<queryresult success='true'
    error='false'
    numpods='2'
    datatypes=''
    timedout=''
    timedoutpods=''
    timing='0.751'
    parsetiming='0.216'
    parsetimedout='false'
    recalculate='http://www4b.wolframalpha.com/api/v2/recalc.jsp?id=MSPa2715236aaf6db55age00000025hbhc18c61h80c4&amp;s=10'
    id='MSPa2716236aaf6db55age00000019f566b957ic219h'
    host='http://www4b.wolframalpha.com'
    server='10'
    related='http://www4b.wolframalpha.com/api/v2/relatedQueries.jsp?id=MSPa2717236aaf6db55age000000535a701459c5c90a&amp;s=10'
    version='2.6'>
 <pod title='Input interpretation'
     scanner='Identity'
     id='Input'
     position='100'
     error='false'
     numsubpods='1'>
  <subpod title=''>
   <plaintext>Tell me a joke.</plaintext>
  </subpod>
 </pod>
 <pod title='Result'
     scanner='Data'
     id='Result'
     position='200'

But im getting the error:

04-06 22:19:14.348: D/TAG(30413): java.net.MalformedURLException: Protocol not found:

What am I doing wrong ?

Note that I am getting this responseText from a server. So if theres any problem with the xml itself, do tell me how to manipulate the string, instead of suggesting me to change the xml itself.

Jon Skeet · Accepted Answer · 2015-04-06 16:59:25Z

14

The problem is that you're passing in the XML content itself - but DocumentBuilder.parse(String) accepts a URL to load the XML from - not the content itself.

You probably want to use DocumentBuilder.parse(InputSource) instead, having created an InputSource from a StringReader wrapping the XML:

Document document = builder.parse(new InputSource(new StringReader(xml)));

answered Apr 6, 2015 at 16:59

Jon Skeet

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1 Comment

harveyslash Over a year ago

The correct answer from the himself. Thanks, it works!!! ill accept your answer as soon as i am allowed to :P

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