Extract links from string optimization

Like AdamPro13 said above using NSDataDetector you can easily get all the URLs, see it the following code :

let text = "http://www.google.com. http://www.bla.com"
let types: NSTextCheckingType = .Link
var error : NSError?

let detector = NSDataDetector(types: types.rawValue, error: &error)        
var matches = detector!.matchesInString(text, options: nil, range: NSMakeRange(0, count(text)))

for match in matches {
   println(match.URL!)
}

It outputs :

http://www.google.com
http://www.bla.com

Updated to Swift 2.0

let text = "http://www.google.com. http://www.bla.com"
let types: NSTextCheckingType = .Link

let detector = try? NSDataDetector(types: types.rawValue)

guard let detect = detector else {
   return
}

let matches = detect.matchesInString(text, options: .ReportCompletion, range: NSMakeRange(0, text.characters.count))

for match in matches {
    print(match.URL!)
}

Remember to use the guard statement in the above case it must be inside a function or loop.

I hope this help.

And that is the answer for Swift 5.0

let text = "http://www.google.com. http://www.bla.com"

func checkForUrls(text: String) -> [URL] {
    let types: NSTextCheckingResult.CheckingType = .link

    do {
        let detector = try NSDataDetector(types: types.rawValue)

        let matches = detector.matches(in: text, options: .reportCompletion, range: NSMakeRange(0, text.count))
    
        return matches.compactMap({$0.url})
    } catch let error {
        debugPrint(error.localizedDescription)
    }

    return []
}

checkForUrls(text: text)

Very helpful thread! Here's an example that worked in Swift 1.2, based on Victor Sigler's answer.

    // extract first link (if available) and open it!
    let text = "How technology is changing our relationships to each other: http://t.ted.com/mzRtRfX"
    let types: NSTextCheckingType = .Link

    do {
        let detector = try NSDataDetector(types: types.rawValue)
        let matches = detector.matchesInString(text, options: .ReportCompletion, range: NSMakeRange(0, text.characters.count))
        if matches.count > 0 {
            let url = matches[0].URL!
            print("Opening URL: \(url)")
            UIApplication.sharedApplication().openURL(url)
        }

    } catch {
        // none found or some other issue
        print ("error in findAndOpenURL detector")
    }

There's actually a class called NSDataDetector that will detect the link for you.

You can find an example of it on NSHipster here: http://nshipster.com/nsdatadetector/

Swift 5.8.1

import Foundation

extension String {
    var urls: [String] {
        var urlsArr = [String]()
        do {
            let detector = try NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
            detector.enumerateMatches(in: self, options: [], range: NSMakeRange(0, self.utf16.count), using: { (result, _, _) in
                if let nsrange = result?.range {
                    urlsArr.append((self as NSString).substring(with:nsrange))
                }
            })
        } catch let error {
            print(error.localizedDescription)
        }
        return urlsArr
    }
}

Usage:

let str = "🤩 Hello world. https://www.google.com , blabla ❤️ apple.com, www.test.com"
print(str.urls) //["https://www.google.com", "apple.com", "www.test.com"]

I wonder if you realise that every single time that you call countElements, a major complex function is called that has to scan all the Unicode characters in your string, and extract extended grapheme clusters from them and count them. If you don't know what an extended grapheme cluster is then you should be able to imagine that this isn't cheap and major overkill.

Just convert it to an NSString*, call rangeOfString and be done with it.

Obviously what you do is totally unsafe, because http:// doesn't mean there is a link. You can't just look for strings in html and hope it works; it doesn't. And then there is https, Http, hTtp, htTp, httP and so on and so on and so on. But that's all easy, for the real horror follow the link in Uttam Sinha's comment.

As others have pointed out, you are better off using regexes, data detectors or a parsing library. However, as specific feedback on your string processing:

The key with Swift strings is to embrace the forward-only nature of them. More often than not, integer indexing and random access is not necessary. As @gnasher729 pointed out, every time you call count you are iterating over the string. Similarly, the integer indexing extensions are linear, so if you use them in a loop, you can easily accidentally create a quadratic or cubic-complexity algorithm.

But in this case, there's no need to do all that work to convert string indices to random-access integers. Here is a version that I think is performing similar logic (look for a prefix, then look from there for a " character - ignoring that this doesn't cater for https, upper/lower case etc) using only native string indices:

func extractAllLinks(text: String) -> [String] {
    var links: [String] = []
    let prefix = "http://"
    let prefixLen = count(prefix)

    for var idx = text.startIndex; idx != text.endIndex; ++idx {
        let candidate = text[idx..<text.endIndex]
        if candidate.hasPrefix(prefix),
           let closingQuote = find(candidate, "\"") {
            let link = candidate[candidate.startIndex..<closingQuote]
            links.append(link)
            idx = advance(idx, count(link))
        }
    }
    return links
}

let text = "This contains the link \"http://www.whatever.com/\" and"
         + " the link \"http://google.com\""

extractAllLinks(text)

Even this could be further optimized (the advance(idx, count()) is a little inefficient) if there were other helpers such as findFromIndex etc. or a willingness to do without string slices and hand-roll the search for the end character.