arr = [
{"id":"1"},
{"id":"2"}
];
For some reason I want to change the "id" to "uid". I am stuck here
arr.forEach(function(i){
});
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4 Answers
arr = [{
"id": "1"
},
{
"id": "2"
}
];
arr.forEach(function(i) {
i.uid = i.id;
delete i.id;
});
console.log(arr);This will modify arr. If you want a copy of arr that has the changed structure, follow Mritunjay's answer.
Comments
Just do like bellow:
arr = [{
"id": "1"
},
{
"id": "2"
}
];
arr = arr.map(function(obj) {
return {
"uid": obj.id
}
});
console.log(arr);
1 Comment
Downgoat
This returns a new object in place of the old one, if OP decides to add more elements to the object, this won't work as properly without back and forth editing
Here you go:
arr.map(function (a) {
a.uid=a.id;delete a.id;
return a;
});
This just goes through the array, renames it, and returns the value.
Snippet:
var arr = [{
"id": "1"
}, {
"id": "2"
}];
arr = arr.map(function(a) {
a['uid'] = a['id'];
delete a['id'];
return a;
});
console.log(arr);You mentiond
forEach so here's an answer with it.
arr.forEach(function (a) {
a.uid=a.id;delete a.id;
});
Comments
arr = [{
"id": "1"
},
{
"id": "2"
}
];
arr = arr.map(function(item, index) {
// forget about the index, e.g. running from 0 to arr.length - 1
return {
uid: item.id
};
});
console.log(arr);2 Comments
C Nimmanant
nah.. lots of duplicate with others.. but fun anyways.
Downgoat
this is the exact same as Mritunjay's answer