undefined index invalid argument for loop error

Question

Please point me in the right direction here Im trying to do the following:

Multiple select boxes are generated for each eventid
User choose who they think will win each event
The name of each selectBox is the event id assigned to variable $id
At end of while loop I want to extract the array $id value in For loop, however im getting error "undefined offset & invalid argument" on my for loop...

Here is my form

enter image description here

    $i=0;//counter
    while($row=mysql_fetch_array($result)){

    $team1 = $row['team1'];
    $team2 = $row['team2'];
    $id[$i]= $row['event_id']; 

    echo'<h3>'.$team1.' VS '.$team2.'</h3>';
    echo'<select name="'.$id[$i].'">';
            echo'<option value="'.$row['team1'].'">'.$team1.'</option>';
            echo'<option value="'.$row['team2'].'">'.$team2.'</option>';
            echo'</select>';    
        $i++;
    }//while

Here is my for loop giving error, I suspect problem is in the $_POST['$id']...

if(isset($_POST['submit'])){    

    foreach($_POST[$id] as $eventId => $winner){
     echo'<h3>'.$eventId.'</h3>';
}//for loop
}//end isset

Any help will be greatly appreciated

@Lashane is this what you are asking $id[$i]= $row['event_id']; WHERE $row['event_id']; is retrieved from database — Marilee
– Marilee, Commented Apr 17, 2015 at 17:59
possible duplicate of PHP: "Notice: Undefined variable" and "Notice: Undefined index" — chris85
– chris85, Commented Apr 17, 2015 at 18:00
What is the exact error message and to what line does it relate? — ficuscr
– ficuscr, Commented Apr 17, 2015 at 18:01
I think you need to change $id to just id in your code. You are using a variable when you are actually trying to use a constant. — Maximus2012
– Maximus2012, Commented Apr 17, 2015 at 18:01

Digits · Accepted Answer · 2015-04-17 18:06:54Z

2

$id is defined as an array here$id[$i]= $row['event_id'];. Arrays can not be used as a key in a foreach array or otherwise. This is what is causing you an error on this line

foreach($_POST[$id] as $eventId => $winner){ //$id is an array of values
    echo'<h3>'.$eventId.'</h3>';
}//for loop

You have to make a second foreach statement for the $id then use the id values in your current foreach statement.

foreach( $id as $key => $val ) {
foreach( $_POST[$val] as $eventId => $winner){

answered Apr 17, 2015 at 18:06

Digits

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1 Comment

Marilee Over a year ago

thank you very much for your help, I tweaked it a bit but it works like a bomb

earl · Accepted Answer · 2015-04-17 18:24:28Z

0

You don't know what the event_id values are on the action page, so I think you'll have to query for those again something like:

if(isset($_POST['submit'])){
    /* do your query here */
    $data = array();
    while($row=mysql_fetch_array($result)){
     $data[] = $_POST[$row['event_id']];
    }

    foreach($data as $key => $value){
        print_r($_POST[$value]);
        echo "<br>";
    }
}

answered Apr 17, 2015 at 18:24

earl

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