How to check if string consists of letters only by using regular expression.
I know how to check only one character: if (s.matches("\\w")) System.out.println(true);
But I don`t understand how to check full string.
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3 Answers
\w includes numbers in its expression. You could do
if (s.matches("[a-zA-Z]*")) {
...
}
where * matches 0 or more characters. Note that empty strings are matched by this pattern also so you may want to use the + quantifier instead
Comments
Replace matches("\\w") with matches("^[A-Za-z]*$"). This should instruct the matcher to expect the string to be made up entirely of 0 or more letters (case insensitive).
The * denotes zero or more repetitions of what preceeds it. On the other hand, the + expects at least one instance of whatever it is that preceeds it, thus, the * operator can potentially match an empty string, which I do not know if it is something which you are after.
Comments
You can use regex matching [a-zA-Z] instead, of looking for the single character w, and add the + to specify you want all characters.
Something like:
System.out.println(s1.matches("[a-zA-Z]+"));
should do the trick.
