Expanding an array in BASH [duplicate]

Question

I have an array:

allChapters=('1' '2' '3' '4' '5' '6' '7' '8' '9' '10' '11' '12' '13' '14' 'A' 'B' 'C' 'D' 'E' 'F' 'G' 'H' 'I')

I need to run a command that takes specifying parameters like:

prince index.html 1.html 2.html 3.html 4.html 5.html 6.html 7.html 8.html 9.html 10.html 11.html 12.html 13.html 14.html A.html B.html C.html D.html E.html F.html G.html H.html I.html  -o doc.pdf

Is there a way to expand an array without manually typing it all so I can just add to the array and not have to modify the command?

Something like:

prince ${allChapters[*]}.html -o doc.pdf

John Kugelman · Accepted Answer · 2015-04-20 17:34:10Z

8

This works:

prince "${allChapters[@]/%/.html}" -o doc.pdf

That replaces the empty string at the end of each entry with the desired extension.

edited Apr 20, 2015 at 17:34

John Kugelman

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answered Apr 20, 2015 at 17:22

glenn jackman

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2 Comments

GameDeveloper Over a year ago

Fantastic. Thank you for this! Where could I have looked this up? Googling wasn't helpful for a reference doc.

glenn jackman Over a year ago

Go to the source: the GNU bash manual. In this case, the answer is in the parameter expansion section. Scroll down to read about ${parameter/pattern/string} and you'll find: "If parameter is an array variable subscripted with ‘@’ or ‘*’, the substitution operation is applied to each member of the array in turn, and the expansion is the resultant list."

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