JSON Simple: integer parsing

Question

I have a problem parsing JSON integer in my REST service. Parsing String and double type works fine

Working:

JSONParser parser = new JSONParser();
Object obj = null;
try {
    obj = parser.parse(input);
} catch (ParseException e) {
    e.printStackTrace();
}
JSONObject jsonObject = (JSONObject) obj;   

//---------------
String uName = (String) jsonObject.get("userName");
double iPrice = (Double) jsonObject.get("itemPrice");

Not working:

int baskId = (Integer) jsonObject.get("basketId");

I tried to convert the basketId in my basket class to String, and then it functions ok, so code is okay, and link is working, however, when I cast it back to int, I get 500 server error. I am using it to create a new basket with some numeric ID, so I use the @POST annotation and the JSON in the payload is as follows:

{"basketId":50}

I don't get it...

EDIT: I do get it...JSON simple accepts just bigger types of Java primitives, so integer and float are a no-no

What library do you use ? Doesn't it have a getInt(...) method ? — Titus
– Titus, Commented Apr 21, 2015 at 11:03
Its JSON simple library, code.google.com/p/json-simple, no getInt, just get. Double gets parsed fine. I am using chrome rest client plugin, so i get 500 Internal server error. There is no error in eclipse — Norgul
– Norgul, Commented Apr 21, 2015 at 11:09
Integer.parseInt().. stackoverflow.com/questions/15699953/… — bgth
– bgth, Commented Apr 21, 2015 at 11:15
In that case you have to check the type of the value basketId before you cast it. You can do that using instanceof or jsonObject.get("basketId").getClass() — Titus
– Titus, Commented Apr 21, 2015 at 11:17

raki · Accepted Answer · 2015-04-21 11:26:24Z

7

In your code jsonObject.get("basketId");returns Long

So using Long for type casting would help you in resolving your error (Long)jsonObject.get("basketId");

If you really need Integer then type cast it to inetger as follows

((Long)jsonObject.get("basketId")).intValue()

answered Apr 21, 2015 at 11:26

raki

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1 Comment

Norgul Over a year ago

This actually works...hmm...it is possible that JSON Simple accepts just bigger types, since I just tried with float, and it doesn't work either.

libik · Accepted Answer · 2015-04-21 11:06:25Z

0

If you parse it as String, you cant do something like this :

String x = "10";
int y = (int) x;

But you can use this method

String x = "10";
int y = Integer.valueOf(x);

answered Apr 21, 2015 at 11:06

libik

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2 Comments

Norgul Over a year ago

It doesn't do me good, since basket constructor is Basket(int basketId)...I would have to put then all kinds of limitations client-side, and do the conversions both ways

libik Over a year ago

Well, we can use jackson, than the de/serialization is done automatically

Santo · Accepted Answer · 2015-04-21 11:13:35Z

0

Rather than : int baskId = (Integer) jsonObject.get("basketId");

Use : int baskId = jsonObject.getInt("basketId");

It is in the official documentation : http://www.json.org/javadoc/org/json/JSONObject.html#getInt(java.lang.String)

answered Apr 21, 2015 at 11:13

Santo

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1 Comment

Titus Over a year ago

He doesn't use that library, he uses code.google.com/p/json-simple and in this library JSONObject is just an extension of Map and it doesn't have a getInt(...) method.

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