c code: for loop compiles with gcc but doesn't run

Question

I'm new to c programming. I'm trying to print numbers 1 to 10.

#include <stdio.h>

int main(){
    int i;
    for(i=1; i<11; i++){
        printf("%s\n", i);
    }
    getchar();
}

It compiles in powershell when I type: gcc .\forloop.c but when I try to run the program with ./a I get this error message:

a.exe has stopped working

Any help would be appreciated.

@CarlNorum I'm using the -Wall option to compile now. Thanks for the tip. — hedgesketch
– hedgesketch, Commented Apr 23, 2015 at 3:51

kaylum · Accepted Answer · 2015-04-23 01:09:45Z

4

printf("%s\n", i);

That tries to print a string. i is an integer. So it will crash when it dereferences i as a string.

Try

printf("%d\n", i);

answered Apr 23, 2015 at 1:03

kaylum

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1 Comment

@AlanAu so we agreed to disagree, then let's please delete all these comments.