Go through an array to find a multiple of a number with JavaScript

Question

I have to go through the following array and find the number that isn't a multiple of eight (58 at the end). I've been trying to figure out how to do it but nothing I tried really worked.

var multiplesOfEight = [8,16,24,32,40,58];

I tried this

var multiplesOfEight = [8,16,24,32,40,58];
if (multiplesOfEight % 8 === 0) {
    console.log("Multiple of 8");
} else {
    console.log("Wrong number");
}

and it just logs "Wrong number", I was expecting it to repeat "multiple of 8" five times and then wrong number but I guess that if/else is taking the array as a whole or something? An explanation of what exactly is happening with this if/else would also be appreciated.

you should use a for loop!

Michail Michailidis
– Michail Michailidis

2015-04-24 02:37:29 +00:00
Commented Apr 24, 2015 at 2:37 — Michail Michailidis
– Michail Michailidis, Commented Apr 24, 2015 at 2:37

meteor · Accepted Answer · 2015-04-24 02:39:28Z

1

for(var i=0;i<multiplesOfEight.length;i++){
if (multiplesOfEight[i] % 8 === 0) {
    console.log("Multiple of 8");
} else {
    console.log("Wrong number");
}
}

edited Apr 24, 2015 at 2:39

answered Apr 24, 2015 at 2:38

meteor

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2 Comments

meteor Over a year ago

Jus modified it.. Typo

RobG Over a year ago

Consider console.log(mutiplesOfEight[i] % 8? 'Mulitple of 8' : 'Wrong number'). ;-)

IronFlare · Accepted Answer · 2015-04-24 02:42:16Z

0

You can accomplish this using a for loop, however you don't even need to store the array in a separate variable. With this syntax, you can integrate the array right into the for loop itself:

for (var multiple of [8,16,24,32,40,58]) { 
    if (multiple % 8 === 0) {
        console.log("Multiple of 8");
    } 
    else {
        console.log("Wrong number");
    }
}

http://jsfiddle.net/IronFlare/37ju75c6/

answered Apr 24, 2015 at 2:42

IronFlare

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Comments

prola · Accepted Answer · 2015-04-24 02:47:00Z

0

var multiplesOfEight = [8,16,24,32,40,58];
for(var i=0;i<multiplesOfEight.length;i++){
if (multiplesOfEight[i] % 8 === 0) {
    console.log("Multiple of 8");
} else {
    console.log("Wrong number");
}
}

answered Apr 24, 2015 at 2:47

prola

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1 Comment

prola Over a year ago

You want to compare multiplesOfEight at i

userlond · Accepted Answer · 2015-04-24 02:48:02Z

0

Simpler with forEach statement (open console of browser to view result when running snippet):

[8,16,24,32,40,58].forEach(function(i) {
  if (i % 8 === 0) console.log(i + " is multiple of 8");
  else console.log(i + " is wrong number");
});

edited Apr 24, 2015 at 2:48

answered Apr 24, 2015 at 2:42

userlond

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Comments

typically · Accepted Answer · 2015-04-24 02:51:36Z

0

You need to check whether each element of the array modulo 8 equals 0.

An option is to use Array#forEach.

var multiplesOfEight = [8,16,24,32,40,58];

multiplesOfEight.forEach(function(num, index){
   if (num % 8 === 0) {
       console.log("The number " + num + " at index " + index + " is divisible by 8");
   } else {
       console.log("The number " + num + " at index " + index + " is a wrong number");
   }
});

answered Apr 24, 2015 at 2:51

typically

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Comments

Tomas Ramirez Sarduy · Accepted Answer · 2015-04-24 02:54:21Z

0

What happens if you iterate over the numbers? ;)

[8, 16, 24, 32, 40, 58].forEach(function(n) {
  if(n % 8 == 0) 
     console.log(n + " is multiple of 8");
  else
     console.log(n + " is not multiple of 8");
});

answered Apr 24, 2015 at 2:54

Tomas Ramirez Sarduy

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