I have a string Test123(45) and I want to remove the numbers within the parenthesis. How would I go about doing that?
So far I have tried the following:
string str = "Test123(45)";
string result = Regex.Replace(str, "(\\d)", string.Empty);
This however leads to the result Test(), when it should be Test123().
tis replaces all parenthesis, filled with digits by parenthesis
string str = "Test123(45)";
string result = Regex.Replace(str, @"\(\d+\)", "()");
\d+(?=[^(]*\))
Try this.Use with verbatinum mode @.The lookahead will make sure number have ) without ( before it.Replace by empty string.
See demo.
test 444). It will even replace a number if it is followed by letters before a closing round bracket: test 444string). If these cases are OK, then I have no questions. :)
string str = "Test123(45)";
string result = Regex.Replace(str, @"\(\d+\)", "()");
Regex.Replace(str, @"\(\d+\)", "()") will work for string in format (DigitDigitDigit); [result ()]; it will not remove Digits if string in format (DigitSomethingDigit); [result (DigitSomethingDigit)]you can also try this way:
string str = "Test123(45)";
string[] delimiters ={@"("};;
string[] split = str.Split(delimiters, StringSplitOptions.None);
var b=split[0]+"()";
Remove a number that is in fact inside parentheses BUT not the parentheses and keep anything else inside them that is not a number with C# Regex.Replace means matching all parenthetical substrings with \([^()]+\) and then removing all digits inside the MatchEvaluator.
Here is a C# sample program:
var str = "Test123(45) and More (5 numbers inside parentheses 123)";
var result = Regex.Replace(str, @"\([^()]+\)", m => Regex.Replace(m.Value, @"\d+", string.Empty));
// => Test123() and More ( numbers inside parentheses )
To remove digits that are enclosed in ( and ) symbols, the ASh's \(\d+\) solution will work well: \( matches a literal (, \d+ matches 1+ digits, \) matches a literal ).
