extract data from array that begins with "http" only

Question

I have an array $all_urls. If I do print_r($all_urls);, it will return the following data:

Array (
[0] => http://www.domain.com
[1] => https://www.domain.com
[2] => http://www.domain.com/my-account/
[3] => https://www.facebook.com/
[4] => /test
[5] => http://domain.com/wp-content/uploads/logos-5.jpg 
[6] => 'http://domain.com/wp-content/themes/'
[7] => '//mattressandmore.com/wp-content/plugins'
)

I would like to extract and list the items that contain "http://" only.

that begins with 'http://' or has 'http://' in it? ie, should element 6 in your array match? — pala_
– pala_, Commented May 2, 2015 at 8:19
Then are you sure the answer you commented on after changing the regexp actually works? it is looking for http only at the start of a string — pala_
– pala_, Commented May 2, 2015 at 8:21
@pala_ hmm no it didnt.. i didnt realise until you mentioned it but it isnt including the 6th element — user3436467
– user3436467, Commented May 2, 2015 at 8:22

Adviov · Accepted Answer · 2015-05-02 08:01:31Z

1

Use this code to filter only the values that begin with http and return a new array:

array_filter($arr, function ($var) {
    return stripos($var, 'http', -strlen($var)) !== FALSE;
});

answered May 2, 2015 at 8:01

Adviov

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Comments

vanadium23 · Accepted Answer · 2015-05-02 07:58:14Z

0

Try to use array_walk function like this:

array_walk($all_urls, function(function(&$value, $index){
    if (preg_match('/^http/', $value)) {
        echo $index . " " . $value . "\n";
    }
});

Also you can just iterate on array with foreach:

foreach($all_urls as $index => $value) {
    if (preg_match('/^http/', $value)) {
        echo $index . " " . $value . "\n";
    }
}

answered May 2, 2015 at 7:58

vanadium23

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7 Comments

user3436467 Over a year ago

thanks very much. The second solution works well but it did return some https:// whereas i only want http://.. i just updated the preg_match to '/^http:/' and it works pefectly

user3436467 Over a year ago

and finally, if no matches found, how to echo "now matches found" ?

pala_ Over a year ago

@user3436467 remove the ^ from ^http to change it to match anywhere in the string

user3436467 Over a year ago

also just noticed the 6th element didnt appear, the one that contains a apostrophe at the begining and end 'http://domain.com/wp-content/themes/'

user3436467 Over a year ago

okay great. removing the ^ worked.. just need to include if no matches found echo "no matches found"

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