I have a string and Im trying to get the index of value "bad" and for some reason it throws me an error.
>>> s = "This dinner is not that bad!"
>>> l = s.split()
>>> bad_index_value = l.index('bad')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: list.index(x): x not in list
Actually you have not bad in your list its bad!. if you want to find the index of bad you can strip the element with '!':
>>> s = "This dinner is not that bad!"
>>> s.strip().split()
['This', 'dinner', 'is', 'not', 'that', 'bad!']
>>>
>>> l=s.strip('!').split()
>>> l.index('bad')
5
>>> s = "This dinner is not that bad !"
>>> l = s.split()
>>> bad_index_value = l.index('bad') # will give you the index.
Technically bad is not present in your input This dinner is not that bad!, its bad!
>>> import re
>>> s = "This dinner is not that bad!"
>>> re.sub(r'[^\w\s]','',s).split().index('bad')
5
>>>
You can use re.split() instead of string.split(). The use of regular expressions allows specifying both the ! and whitespace (\s) as a delimiter:
>>> import re
>>> s = "This dinner is not that bad!"
>>> l = re.split("[!\s]", s)
>>> bad_index_value = l.index('bad')
>>> bad_index_value
5
Note that l now contains a trailing empty string (because one of the delimiters is at the end of the string):
>>> l
['This', 'dinner', 'is', 'not', 'that', 'bad', '']
If necessary, you can use a list comprehension to remove it:
>>> l= [x for x in re.split("[!\s]", s) if x]
>>> l
['This', 'dinner', 'is', 'not', 'that', 'bad']
No need to split the string into a list just run
>>> s = "This dinner is not that bad!"
>>> s.find("bad")
24 # s[24] = 'b'
