How to extract a complex version number using sed?

Question

I use sed in CentOs to extract version number and it's work fine:

echo "var/opt/test/war/test-webapp-4.1.56.war" | sed -nre 's/^[^0-9]*(([0-9]+\.)*[0-9]+).*/\1/p'

But my problem is that i am not able to extract when the version is shown like this:

var/opt/test/war/test-webapp-4.1.56-RC1.war

I want to extract the 4.1.56-RC1 if it is present.

Any ideas ?

EDIT 2

Ok to be clear take this example, with a path:

Sometimes the path contains only a serial number like this var/opt/test/war/test-webapp-4.1.56.war and sometimes it contains a series of numbers and letters like this "var/opt/test/war/test-webapp-4.1.56-RC1.war

The need is to recover either 4.1.56 or 4.1.56-RC1 depending on the version present in the path. With sed or grep, no preference.

This seems to work but the .war is shown at the end:

echo "var/opt/test/war/test-webapp-4.1.56.war" | egrep -o '[0-9]\S*'

why don't you just say echo "version ..." | awk '{print $2}'? — fedorqui
– fedorqui, Commented May 5, 2015 at 19:37
because maybe the extract is make from a path like this: /var/opt/test/war/test-webapp-4.1.56-RC1.war — Marc
– Marc, Commented May 5, 2015 at 19:38
I'm going to vote close based "Unclear what you're asking" This question will be of no help to future users if you don't update it. — Pedro Lobito
– Pedro Lobito, Commented May 5, 2015 at 19:44
@Marc wrt because maybe the extract is make from a path like this: /var/opt/test/war/test-webapp-4.1.56-RC1.war - so what if it was? Don't answer that in a comment but instead edit your question to show examples of all possible version info formats that you want to be able to handle along with the expected output for each. — Ed Morton
– Ed Morton, Commented May 5, 2015 at 19:50

dawg · Accepted Answer · 2015-05-05 20:07:16Z

1

Little unclear what you are after, but this seems to be in the general direction.

Given:

$ echo "$e"
/var/opt/test/war/test-webapp-4.1.56-RC1.war
/var/opt/test/war/test-webapp-RC1.war
Version 4.2.4 (test version)

Try:

$ echo "$e" | egrep -o '(\d+\.\d+\.\d+-?\w*)'
4.1.56-RC1
4.2.4

answered May 5, 2015 at 20:07

dawg

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score 1 · Accepted Answer · 2015-05-06 09:30:29Z

1

The following will match the first digit up to 2 digits in length ({1,2}, second up to 2 digits and the last up to 4 digits followed by anything non-space up to a space.

grep -o '[0-9]\{1,2\}.[0-9]\{1,2\}.[0-9]\{1,4\}'

edited May 6, 2015 at 9:30

answered May 6, 2015 at 4:40

user4401178

Comments

karthik manchala · Accepted Answer · 2015-05-05 19:43:25Z

0

Just add (-[a-zA-Z]+[0-9]+) to your regex:

echo "Version 4.2.4 (test version)" | sed -nre 's/^[^0-9]*(([0-9]+\.)*[0-9]+(-[a-zA-Z]+[0-9]+)).*/\1/p'

answered May 5, 2015 at 19:43

karthik manchala

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1 Comment

Marc Over a year ago

Thanks. I used your code and I modified as follows for my needs:

echo "/var/opt/test/war/test-webapp-4.1.56-RC1.war" | sed -nre 's/^[^0-9]*(([0-9]+\.)*[0-9]+(-[a-zA-Z]*[0-9]*[a-zA-Z]*)*).*/\1/p'

Eric Renouf · Accepted Answer · 2015-05-05 19:39:43Z

0

What about just using whitespace as the delimiter like

echo "Version 4.2.4-RC1 (test version)" | grep -Po "Version\s+\K\S+"

for grep -P says to use Perl style regex, -o shows only the matching part and the \K in the string says not to show everything before it as part of the match

answered May 5, 2015 at 19:39

Eric Renouf

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2 Comments

Marc Over a year ago

it's good idea but maybe the extract is make from a path like this: /var/opt/test/war/test-webapp-4.1.56-RC1.war. It's not the same format each timee

Eric Renouf Over a year ago

In that case, is it reliable that it's always the 3rd and alter in the last part? Could you do something like basename <path> | cut -f 3- -d- | cut -f1 -d.

Vytenis Bivainis · Accepted Answer · 2015-05-05 22:23:09Z

0

This passes both tests

egrep -o '[0-9]\S*'

Unfortunately, not all greps support -o, but grep in Linux does.

answered May 5, 2015 at 22:23

Vytenis Bivainis

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Comments

NeronLeVelu · Accepted Answer · 2015-05-06 05:52:13Z

0

echo "Version 4.2.4 (test version)" | sed 's/Version[[:space:]]*\([^[:space:](]*\).*/\1/'

But like every extraction, you need to define what you want, not what could exist and extract it (or change your request).

answered May 6, 2015 at 5:52

NeronLeVelu

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