How to get values from array using POST method

Question

How to get value in another page using the POST method?

<label>
    <input type="radio" value = "1" name="jsq[1]" checked>1
</label>
<label>
    <input type="radio" value = "2" name="jsq[1]">2
</label></br>
<label>
    <input type="radio" value = "3" name="jsq[1]">3
</label>
<label>
    <input type="radio" value = "4" name="jsq[1]">4
</label></br>
<label>
    <input type="radio" value = "5" name="jsq[1]">5
</label>

I want to get value of jsq[1] in myarr[1]. How can I do that?

$myarr[1] = $_POST['jsq[1]'];

$_POST['jsq'][1'] - all of your inputs have the same name so only 1 of the values will come through — FuzzyTree
– FuzzyTree, Commented May 6, 2015 at 14:26
$myarr[1] = $_POST['jsq'][1]; You might have found it yourself with a simple test by printing the content of $_POST. ;) — user3849602
– user3849602, Commented May 6, 2015 at 14:28
@FuzzyTree — They're radio buttons, you're only going to get one of them anyway. — Quentin
– Quentin, Commented May 6, 2015 at 14:33

ErikL · Accepted Answer · 2015-05-06 14:29:32Z

5

Without going into the question why you're naming them jsq[1] an not just jsq...

you're almost there, but it should be

$myarr[1] = $_POST['jsq'][1];

It's by the way always a good idea to check this king of things using print_r($_POST); or var_dump($_POST);

answered May 6, 2015 at 14:29

ErikL

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