Yii2 populate update form with values stored in array

Question

I have created a form with the following fields and use json encode before saving to a single database field.

Now I need to populate the fields when using the update form however I am unsure as i can't find any yii2 example.

<?= $form->field( $model, 'seo_information[field1]' )
          ->textInput( [ 'maxlength' => 255 ] )
          ->label('Array Field 1) ?>

<?= $form->field( $model, 'seo_information[field2]' )
         ->textInput( [ 'maxlength' => 255 ] )
         ->label('Array Field 2') ?>

<?= $form->field( $model, 'seo_information[field3]' )
         ->textInput( [ 'maxlength' => 255 ] )
         ->label('Array Field 3') ?>

Controller Create Code

public function actionCreate()
{
    $model = new Article();
    $model->user_id = Yii::$app->user->id;

    if ($model->load(Yii::$app->request->post())) 
    {
        $seo_information = $_POST['Article']['seo_information'];
        $model->seo_information = json_encode($seo_information); 
        $model->save();
        return $this->redirect(['view', 'id' => $model->id]);
    } 
    else 
    {
        return $this->render('create', [
            'model' => $model,
        ]);
    }
}

Could you show how you do json_encode? Is it in controller or model? — robsch
– robsch, Commented May 10, 2015 at 9:41
public function actionCreate() { $model = new Article(); $model->user_id = Yii::$app->user->id; if ($model->load(Yii::$app->request->post())) { $seo_information = $_POST['Article']['seo_information']; $model->seo_information = json_encode($seo_information); $model->save(); return $this->redirect(['view', 'id' => $model->id]); } else { return $this->render('create', [ 'model' => $model, ]); } } Could do with some validation. — Connor Brough
– Connor Brough, Commented May 10, 2015 at 11:58
Oh... please put that into your question! Just edit the question and insert the code, please. — robsch
– robsch, Commented May 10, 2015 at 12:06

arogachev · Accepted Answer · 2015-05-10 15:04:02Z

2

This should do it:

else 
{
     $model->seo_information = json_decode($model->seo_information, true); 
     return $this->render('create', [
         'model' => $model,
     ]); 
}

This works also if the value in the db is NULL.

edited May 10, 2015 at 15:04

arogachev

33.6k8 gold badges121 silver badges118 bronze badges

answered May 10, 2015 at 14:10

robsch

9,77810 gold badges69 silver badges107 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Yii2 populate update form with values stored in array

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related