how to print array of chars with its pointer?

Question

I'm trying to do this :

void print(char *string){

int i = 0;

do{

    cout << string[i];
    i++;

} while (string[i] != '/0');

}

But on the output I have some weird results. How can I make this work. Am just trying to print out array of chars with a pointer to a 1st in line. TY

jrok · Accepted Answer · 2015-05-12 16:14:45Z

1

Your null character literal is wrong; you need backslash: '\0'.

answered May 12, 2015 at 16:14

jrok

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1 Comment

wow..can't believe that I didn't check that before posting.Lesson learned. Thank you sir !