Capture a value outputted in terminal with php

Question

I have this function:

exec("sudo /root/modbus/writeForceReg 2 0");

located in a php script. When I execute the script in terminal, it returns either 1 or -1 in the terminal window. My question is how to capture and store these two values in a variable in the same php script?

Take a look into the manual: php.net/manual/en/function.exec.php — Rizier123
– Rizier123, Commented May 13, 2015 at 10:45

davidgiga1993 · Accepted Answer · 2015-05-13 10:57:45Z

1

exec provides a second parameter which can be used to get the output of the process

exec("sudo /root/modbus/writeForceReg 2 0", $output);

If the application is using the stderr instead of stdout you need to use proc_open: http://php.net/manual/en/function.proc-open.php

answered May 13, 2015 at 10:57

davidgiga1993

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