PHP regex Word Boundaries doesnt match end of string

Question

i want to find an exact word has been a string. but if its end of the string, word boundaries failing. i thought because of special turkish chars but second code works expected. where is my mistake?

this code returns 0

$row = "TEDARİKÇİ,MÜŞTERİ";
var_dump( preg_match('#\bMÜŞTERİ\b#iu', $row));

but this one returns 1

$row = "TEDARİKÇİ,MÜŞTERİ";
var_dump( preg_match('#\bMÜŞTERİ$#iu', $row));

The two works well for me and return 1 as expected. eval.in/354283 — Casimir et Hippolyte
– Casimir et Hippolyte, Commented May 13, 2015 at 13:29
There's no problem with \b .See here regex101.com/r/mT0iE7/9 — vks
– vks, Commented May 13, 2015 at 13:34
A word boundary matches position before the first word character in the string, after the last word character in the string, and between two characters in the string, where one is a word character and the other is not a word character, so both examples should work fine. — Danijel
– Danijel, Commented May 13, 2015 at 13:40
i think reason is version differences. my local server has an old php 5.2 but actual server has newer version and its worked normally. thanks for efforts. — MC_delta_T
– MC_delta_T, Commented May 13, 2015 at 13:52
additional info: php regex processor thinks İ (big letter I with dot - turkish special chars) is a word boundary. — MC_delta_T
– MC_delta_T, Commented May 13, 2015 at 13:59

Federico Piazza · Accepted Answer · 2015-05-13 13:48:56Z

2

I though both regex should work but I got same problem as you in regex101. So, in order to fix this you can change your regex to:

$row = "TEDARİKÇİ,MÜŞTERİ";
var_dump( preg_match('#\bMÜŞTERİ(\b|$)#iu', $row));

Working demo

answered May 13, 2015 at 13:48

Federico Piazza

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