ggplot2: Define plot layout with grid.arrange() as argument of do.call()

Question

I want to obtained an unbalanced grid of plots such as

require(ggplot2)
require(gridExtra)

df <- data.frame(value1 = rnorm(200),
                 value2 = rnorm(200),
                 value3 = rnorm(200),
                 value4 = rnorm(200))

p1 <- ggplot(df) + geom_density(aes(x=value1))
p2 <- ggplot(df) + geom_density(aes(x=value2))
p3 <- ggplot(df) + geom_density(aes(x=value3))
p4 <- ggplot(df) + geom_density(aes(x=value4))

grid.arrange(p1, arrangeGrob(p2,p3,p4, ncol=3), heights=c(2.5/4, 1.5/4), ncol=1)

enter image description here

but using a function

myplot <- function(i){
  p <- ggplot(df) + geom_density(aes_string(x=i))
  return(p)
}

and an lapply call

p <- lapply(c("value1","value2","value3","value4"), myplot)
do.call(grid.arrange, c(p))

In this case grid.arrange distribute the plots in a 2 by 2 matrix. But I want to obtain an unbalanced layout as with

grid.arrange(p1, arrangeGrob(p2,p3,p4, ncol=3), heights=c(2.5/4, 1.5/4), ncol=1)

My question is different because in my case the plots are unbalanced. I can't simply pass a list to do.call because I want different heights for different plots (see figure) — CptNemo
– CptNemo, Commented May 18, 2015 at 9:42
So, you want to define a layout. Please adjust your question title and body accordingly. — Roland
– Roland, Commented May 18, 2015 at 9:45
Did some edits. Not sure whether it's OK, not sure exactly what you mean by layout. — CptNemo
– CptNemo, Commented May 18, 2015 at 9:48
Maybe you can use this: stackoverflow.com/a/18428858/1412059 — Roland
– Roland, Commented May 18, 2015 at 9:49
Nested grid.arrange/arrangeGrob calls define a layout. You can't achieve that by just passing heights. — Roland
– Roland, Commented May 18, 2015 at 9:50

baptiste · Accepted Answer · 2015-07-16 21:59:37Z

35

You can now do,

grid.arrange(p1,p2,p3,p4, layout_matrix = rbind(c(1,1,1),c(2,3,4)))

answered Jul 16, 2015 at 21:59

baptiste

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