How to create SessionFactory using Hibernate4 and Spring?

Question

I am having issues trying to manage hibernate to work with spring. I don't know how to initiate a Session class on my code. NetBeans keep me saying that the variable sessionFactory has not been initialized.
The problem I am having is on HibernateTest.java when I try sessionFactory.openSession();

Here is the structure of the project and the code, I hope you can help me, thank you. PS. I am using NetBeans 8.0.1

Structure (Dont have rep to upload an image so ill copy as it follows):
-Hibernate Course
  +Web Pages   -Source Packages
    -com.course.entity
      Gender.java
  -com.source.test
      HibernateTest.java
   -Other Sources
     -src/main/resources
   -<>default package<>
       hibernate.cfg.xml
      spring.xml
   +Dependencies
   +Java Dependencies
   +Project files

spring.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.3.xsd">

    <bean id="sessionFactory"
          class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="configLocation" value="classpath:hibernate.cfg.xml" />
    </bean>
    <tx:annotation-driven />
    <bean id="transactionManager"
      class="org.springframework.orm.hibernate4.HibernateTransactionManager">
        <property name="sessionFactory" ref="sessionFactory" />
    </bean>
    <bean id="userDao" class="com.course.entity.Gender">
        <constructor-arg>
            <ref bean="sessionFactory" />
        </constructor-arg>
    </bean>    
</beans>

Hibernate.cfg.xml:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
  <session-factory>
    <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQL9Dialect</property>
    <property name="hibernate.connection.driver_class">org.postgresql.Driver</property>
    <property name="hibernate.connection.url">jdbc:postgresql://localhost:5432/Hibernate</property>
    <property name="hibernate.connection.username">postgres</property>
    <property name="hibernate.connection.password">admin</property>
    <property name="show_sql">true</property>
    <property name="hbm2ddl.auto">update</property>

    <mapping class="com.course.entity.Gender"/>

  </session-factory>
</hibernate-configuration>

Gender.java

package com.course.entity;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;

@Entity
public class Gender {

    @Id
    @SequenceGenerator(name = "ggender_cod_seq", initialValue = 0)
    @GeneratedValue(generator = "gender_cod_seq", strategy = GenerationType.AUTO)
    private int codeGender;

    private String gender;

    public int getCodeGender() {
        return codeGender;
    }

    public void setCodeGender(int codeGender) {
        this.codeGender = codeGender;
    }

    public String getGender() {
        return gender;
    }

    public void setGender(String gender) {
        this.gender = gender;
    } 
}

HibernateTest.java

package com.source.test;

import com.course.entity.Gender;
import java.text.ParseException;
import org.hibernate.Session;
import org.hibernate.SessionFactory;

public class HibernateTest {

    public static void main(String[] args) throws ParseException {

        Gender gender = new Gender();

        gender.setCodeGender(3);

        gender.setGender("Test");

        SessionFactory sessionFactory;

        Session session = sessionFactory.openSession();

        session.beginTransaction();

        session.save(gender);

        session.getTransaction().commit();

        session.close();
    }
}

Serge Ballesta · Accepted Answer · 2015-05-19 19:28:11Z

1

First, you are not using spring at all in your example, because main in HibernateTest does not try to bootstrap a Spring application context.

What happens is simply that you declare a hibernate session factory, do not initialize it, and try to use it. So yes Netbeans is right, variable sessionFactory is never initialized in your code.

To fix it, you must first choose whether you want to directly use Hibernate and then read and follow a Hibernate tutorial, of use Spring + Hibernate and read and follow a Spring tutorial.

The tutorial form Hibernate manual recommends to use an util class similar to :

import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;

public class HibernateUtil {

    private static final SessionFactory sessionFactory = buildSessionFactory();

    private static SessionFactory buildSessionFactory() {
        try {
            // Create the SessionFactory from hibernate.cfg.xml
            return new Configuration().configure().buildSessionFactory();
        }
        catch (Throwable ex) {
            // Make sure you log the exception, as it might be swallowed
            System.err.println("Initial SessionFactory creation failed." + ex);
            throw new ExceptionInInitializerError(ex);
        }
    }

    public static SessionFactory getSessionFactory() {
        return sessionFactory;
    }

}

and use it to create the Hibernate session factory. But again this does not use Spring.

answered May 19, 2015 at 19:28

Serge Ballesta

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1 Comment

Evandro Over a year ago

Thank you very much. I am planning to use Spring so then I can have just one SessionFactory for the whole program, as SessionFactory demands so much resources of the system.

Lea32 · Accepted Answer · 2015-05-19 18:42:12Z

You need to inject SessionFatory as a spring-managed bean with @Autowired or get it from the Spring application context:

public class HibernateTest {

    public static void main(String[] args) throws ParseException {
        ApplicationContext context = new ClassPathXmlApplicationContext("spring.xml");
        SessionFactory sessionFactory = context.getBean("sessionFactory", SessionFactory.class);

        Gender gender = new Gender();
        gender.setCodeGender(3);
        gender.setGender("Test");      

        Session session = sessionFactory.openSession();
        session.beginTransaction();
        session.save(gender);
        session.getTransaction().commit();
        session.close();
    }
}

Also, you can use @Transational instead of manual transaction management.

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