how to set multiple parameter in preg_replace in php

Question

With the use of preg_replace() I want to change string of http://www.vaidehielink.com/ to www.vaidehielink.com.

I have succeeded to get result of www.vaidehielink.com/ with the following code:

$str = "http://www.vaidehielink.com/";
$pattern= '(http://)';
$copy_date = preg_replace($pattern, "", $str);

But I am looking for a pattern to remove the trailing /

Regular expressions aren't necessary for this. If you really want to find the host part of a URL, you can use PHP's built-in url_parse function instead of your own code. (Of course, if you're just practicing your regular expressions, then go ahead...) — RJHunter
– RJHunter, Commented May 19, 2015 at 19:21

AbraCadaver · Accepted Answer · 2015-05-19 18:25:59Z

1

No need for regex.

$copy_date = str_replace(array('http:', '/'), '', $str);

Or probably the proper tool:

$copy_date = parse_url($str, PHP_URL_HOST);

answered May 19, 2015 at 18:25

AbraCadaver

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5 Comments

Rizier123 Over a year ago

I first fell for the same. He only wants to delete the slash, when it is at the end.

AbraCadaver Over a year ago

OK, where did you see that?

Rizier123 Over a year ago

so that trailing slash can also be removed. <- here

AbraCadaver Over a year ago

Yes, in a host name there can't be a /. So it would be part of the path.

Rizier123 Over a year ago

You're right, but since OP wrote: i want to change string I didn't made the assumption, that it has to be a valid url. But I think now/that would be up to OP, to clarify if his string is a valid url.

Rizier123 · Accepted Answer · 2015-05-19 18:28:13Z

0

Besides, that you are missing delimiters, just change your pattern and your replacement to this:

$pattern= "/^(http:\/\/)(.*?)(\/)?$/";
echo $copy_date = preg_replace($pattern, "$2", $str);

output:

www.vaidehielink.com

Basically your only grab the string between http:// and / if there is one.

edited May 19, 2015 at 18:28

answered May 19, 2015 at 18:23

Rizier123

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7 Comments

Pranay Aher Over a year ago

can you explain the $pattern= "/^(http:\/\/)(.*?)(\/)?$/";

Rizier123 Over a year ago

@abhiAhere ^(http:\/\/) matches http:// at the beginning of the string and (\/)?$ matches / 0 or 1 time at the end of the string; And you just grab the middle part of this, which is (.*?)

Pranay Aher Over a year ago

@ Rizier123 thanks i was googling for explanation of pattern, but not getting appropriate answer .this answer help me a lot,

Rizier123 Over a year ago

@abhiAhere Then I can only recommend you a very useful site: regex101.com <- Just throw/ or test your regex'es in there and to the right you get a really good and detailed explanation

Pranay Aher Over a year ago

@ Rizier123 thanks again.I will go through the link you suggested

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